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2 years ago

Please help me:) thanks!

Chemistry

2 answers:

Olegator [25]2 years ago

5 0

Abracadabra, your answer

2Cl2 contains 4 atoms

NaOH contains 3 atoms

CaCO3 contains 5 atoms

Cloud [144]2 years ago

4 0

Answer:

2Cl2 has 4 atoms

NaOH has 3 atoms

CaCO3 has 5 atoms

Explanation:

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PLZ LOOK AT ALL THE QUESTIONS. IF YOU GET THEM ALL, YOU ARE A GOD!!

Brut [27]

B cause it tells how it moves

7 0

3 years ago

Calculate the density in g/mL of 2.0L of gasoline that weighs 1.26 kg

quester [9]

2.0 L in mL :

2.0 x 1000 => 2000 mL

1.26 kg in g :

1.26 x 1000 => 1260 g

D = mass / volume

D = 1260 / 2000

D = 0.63 g/mL

hope this helps!

5 0

2 years ago

How many phosphorus atoms are present ?

Law Incorporation [45]

Answer:

The answer is option 2.

Explanation:

(PO4)2 = P2O8

Therefore, there are 2 Phosphorus atoms present .

3 0

3 years ago

Consider an insulated container in which water (2.58 g) solidifies at 0 oC and 1 atm on the surface of a 55 g aluminum block. As

yarga [219]

Answer:

17.41°C is the change in temperature of the aluminum block.

Explanation:

Latent heat of fusion water = 334 J/g

Heat required to freeze 1 gram of water = -334 J

Heat required to freeze 2.58 grams of water = Q

$Q=2.58 g\times (-334 J/g)=-861.72 J$

Heat lost by water will be equal to heat gained by the aluminum block

$Q'=-Q$

$Q'= -(-861.72 J)=861.72 J$

Formula used to calculate heat absorbed by substance:

$Q=mc\Delta T$

Where:

Q = heat absorbed by substance

c = specific heat of substance

m = Mass of the substance

ΔT = change in temperature of the substance

We have :

Mass of aluminum block= m= 55 g

Heat capacity of aluminum = c = 0.9 J/g°C

Change in temperature of the aluminum block= ΔT = ?

Heat absorbed by the aluminum = Q'

$861.72 J=55 g\times 0.9 J/g^oC\times \Delta T$

$\Delta T=17.41 ^oC$

17.41°C is the change in temperature of the aluminum block.

8 0

3 years ago

A 55 mL bottle of 12 M HCl was diluted with water to a 2.5 M HCl solution. What is the final volume of the diluted acid?

Angelina_Jolie [31]

The final volume of the diluted acid that was initially in a 55 mL bottle of 12 M HCl and diluted with water to a 2.5 M HCl solution is 264mL.

<h3>How to calculate volume?</h3>

The volume of a solution can be calculated using the following formula:

C1V1 = C2V2

Where;

C1 = initial concentration
C2 = final concentration
V1 = initial volume
V2 = final volume

12 × 55 = 2.5 × V2

660 = 2.5V2

V2 = 264mL

Therefore, the final volume of the diluted acid that was initially in a 55 mL bottle of 12 M HCl and diluted with water to a 2.5 M HCl solution is 264mL.

Learn more about volume at: brainly.com/question/1578538

#SPJ1

4 0

2 years ago