Ok so rewrite the equation for yourself :).
N2 + 3H2 -> 2NH3 (Always check if it is balanced).
Ok so we have 2kg of hydrogen conver this to grams and then to moles.
2kg -> 2000g
2000g divide by R.M.M of H2
R.M.M
2H - 2 * 1 -> 2
2000/2 - 1000 moles.
Look at the ratio of H2 to 2NH3.
We see that we get 2NH3 for every H2 therefore the ratio is 1:2.
This means that we HAVE 2000 moles of 2NH3.
At stp. we know that 1 moles = 22.4 Litres
We have 2000 moles that means that we produce 44800 litres of NH3 at stp.
2000 * 22.4 - 44800
Hope this helps :).
<span><span>K_2</span>C<span>O_3</span>(aq)+Ca(N<span>O_3</span><span>)_2</span>(aq)→ ?</span>
If we break these two reactants up into their respective ions, we get...<span><span>
K^+ </span>+ C<span>O^2_3 </span>+ C<span>a^<span>2+ </span></span>+ N<span>O_−3</span></span>
If we combine the anion of one reactant with the cation of the other and vice-versa, we get...<span>
CaC<span>O_3 </span>+ KN<span>O_3</span></span>
Now we need to ask ourselves if either of these is soluble in water. Based on solubility rules, we know that all nitrates are soluble, so the potassium nitrate is. Alternatively, we know that all carbonates are insoluble except those of sodium, potassium, and ammonium; therefore, this calcium carbonate is insoluble.
This is good. It means we have a driving force for the reaction! That driving force is that a precipitate will form. In such a case, a precipitation reaction will occur, and the total equation will be...<span><span>
K_2</span>C<span>O_3</span>(aq) + Ca(N<span>O_3</span><span>)_2</span>(aq) → CaC<span>O_3</span>(s) + 2KN<span>O_3</span>(aq)</span>
To determine the net ionic equation, we need to remove all ions that appear on both sides of the equation in aqueous solution -- these ions are called spectator ions, and do not actually undergo any chemical reaction.
To determine the net ionic equation, let's first rewrite the equation in terms of ions...
2K^+(aq) + CO_3^{2-}(aq) + Ca^{2+}(aq) + 2NO_3^{-}(aq) → Ca^{2+}(s) + CO_3^{2-}(s) + 2K^+(aq) + 2NO_3^-(aq)
The species that appear in aqueous solution on both sides of the equation (spectator ions) are...
<span>
2K^+,NO_3^-</span>
If we remove these spectator ions from the total equation, we will get the net ionic equation...
CO_3^{2-}(aq) + Ca^{2+}(aq) <span>→</span> CaCO_3(s)
Answser
i didnt do dis my mom has a answer key book
Explanation:
The mass in kg of the water on the roof after the rainstorm is mathematically given as
The mass of the water on the roof after a rainstorm is 1.1 *10^{10}g or 1.1*10^{7}kg
<h3>What is the mass in kg of the water on the roof after the rainstorm? </h3>
Generally, the equation for the Area of the roof is mathematically given as
height of the rain =5.5cm
the volume of the rain on the roof =1.1 * 10^{10} CC
Generally, the equation for mass is mathematically given as
mass=volume*density
In conclusion, the Mass of the water on the roof after a rainstorm is 1.1 *10^{10} or $1.1*10^{7}
Read more about Mass
brainly.com/question/19694949
#SPJ1
