Answer:
A = 1100cm^2
Step by step Explanation:
given the dimensions of width and length of the picture are x+20 by 2x-10 and the frame is a constant 5 cm wider from the edge of the picture to the frame, than the area of the frame is defined as (x+30)(2x)-(x+20)(2x-10) = 30x+200.
If the width is equal to the length which I assume is true if the width is constant.
than x+30=2x, which means x = 30.
if this is true than 30(30)+200 = 1100cm^2
Answer:
B
Step-by-step explanation:
7mn³|7m²n³ ---14mn^5
| m---2n²
LCM=7mn³×m×2n²
=14m²n^5
or LCM of 7,14 =14
Highest power of m=2
Highest power of n=5
LCM=14m²n^5
Answer:
The equation of the line passing through the points (-2,0) and (0,-4)
The equation of the line passing through the points (0,-2) and (4,0)
Option B
x minus 2 y = 4 and 2 x + y = negative 4
Use division or long division (ignore the decimal point)
Then put the decimal in the same spot as the dividend (the number being divided)
