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MAXImum [283]
2 years ago
11

What is the weight of a 3.5 kg dog on the moon? acceleration of gravity is 1.63 m/s?)

Physics
2 answers:
Sav [38]2 years ago
5 0

1.98 kilograms

weight on the moon = (weight on Earth / acceleration of Earth's gravity) x acceleration of the moon's gravity

weight on the moon = (12 kg. / 9.81 m/s^2) x 1.63 m/s^2

weight on the moon = 1.98 kg.

#BrainlyOnlineEducation

#CarryOnLearning

boyakko [2]2 years ago
5 0
1.98 kilograms. I just answered that question like an hour ago and got it right
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Two people walking on a sidewalk have the following
vova2212 [387]

Answer:

X2 is fasteer

x=0 will go to Xi

Explanation:

4 0
3 years ago
An airplane flies with a velocity of 55.0 m/s [ 35° N of W] with respect to the air (this is
rodikova [14]

Answer:

21 m/s.  

Explanation:

The computation of the wind velocity is shown below:

But before that, we need to find out the angles between the vectors

53° - 35° = 18°

Now we have to sqaure it i.e given below

v^2 = 55^2 + 40^2 - 2 · 55 · 40 · cos 18°

v^2 = 3025 + 1600 - 2 · 55 · 40 · 0.951

v^2 = 440.6

v = √440.6

v = 20.99

≈ 21 m/s

Hence, The wind velocity is 21 m/s.  

6 0
3 years ago
The y component of a vector is 36, and the angle between the vector and the x axis is 27 what is the magnitude of the vector
xz_007 [3.2K]

Answer:

Magnitude of Vector = 79.3

Explanation:

When a vector is resolved into its rectangular components, it forms two vector components. These components  are named as x-component and y-component, they are calculated by the following formulae:

x-component of vector = (Magnitude of Vector)(Cos θ)

y-component of vector = (Magnitude of Vector)(Sin θ)

where,

θ = angle of the vector with x-axis = 27°

Therefore, using the values in the equation of y-component, we get:

36 = (Magnitude of Vector)(Sin 27°)

Magnitude of Vector = 36/Sin 27°

<u>Magnitude of Vector = 79.3</u>

3 0
3 years ago
Explain why it is important to keep all variables that might affect the dependent variable, other than the manipulated variable
Inga [223]
<span>You have multiple confounding variables, you cannot accurately conclude the relationship between the manipulated and dependent variable because the other variables that are not controlled for could be the reason for seeing a certain change</span>
5 0
3 years ago
Read 2 more answers
The area of a rectangular park is 4 mi^2. The park has a width that is equal to "w", and a length that is 3 mi longer than the w
goldfiish [28.3K]

Answer:

l= 4 mi   : width of the park

w= 1 mi  : length of the park

Explanation:

Formula to find the area of ​​the rectangle:

A= w*l       Formula(1)

Where,

A is the area of the  rectangle in mi²

w is the  width of the rectangle in mi

l is the  width of the rectangle in mi

Known data

A =  4 mi²

l = (w+3)mi    Equation (1)

Problem development

We replace the data in the formula (1)

A= w*l  

4 = w* (w+3)

4= w²+3w

w²+3w-4= 0

We factor the equation:

We look for two numbers whose sum is 3 and whose multiplication is -4

(w-1)(w+4) = 0 Equation (2)

The values ​​of w for which the equation (2) is zero are:

w = 1 and w = -4

We take the positive value w = 1 because w is a dimension and cannot be negative.

w  = 1 mi  :width of the park

We replace w  = 1 mi  in the equation (1) to calculate the length of the park:

l=  (w+3) mi

l= ( 1+3) mi

l= 4 mi

8 0
3 years ago
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