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mr Goodwill [35]
3 years ago
6

What do pressure and temperature determine about a gas

Physics
1 answer:
NikAS [45]3 years ago
8 0

Answer:

With Boyle's law we have that for a constant temperature and gas quantity the pressure of a gas multiplied by its volume is also constant: This means that under the same temperature, two gases with equal quantity of molecules and equal volume must also have the same pressure, as well as that two gases with equal quantity and pressure must have the same volume.

Explanation:

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Answer:

b

Explanation:

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If a proton were released in the electric field above, what direction would it move?
Afina-wow [57]

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d because the proton would move towards the negative plate

Explanation:

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3 years ago
A Ping-Pong ball with mass 2.5 g is attached by a thread to the bottom of a beaker. When the beaker is filled with water so that
dimaraw [331]

Answer:

0.022m or 2.2cm

Expxlanation:

Step 1:

Data obtained from the question. This includes:

Mass (m) = 2.5g = 2.5/1000 = 2.5x10^-3Kg

Tension (T) = 0.029 N

Density (ρ) = 1000 kg/m3

Acceleration due to gravity (g) = 9.81 m/s2

Diameter (d) =?

Step 2:

Finding an expression to calculate the diameter of the ball. This is illustrated below:

Tension = weight displaced - weight of the ball

Weight displaced = Mass of water x acceleration due to gravity

Mass of water = Density x volume

Mass of water = ρxV

Weight displaced = ρxVxg = ρVg

Weight of the ball = Mass of the ball x acceleration due to gravity

Weight of the ball = mg

Therefore,

Tension = weight displaced - weight of the ball

T = ρVg - mg

Make V the subject of the formula

T = ρVg - mg

T + mg = ρVg

Divide both side by ρg

V = ( T + mg) /ρg. (1)

Recall that the ball is spherical in shape and the Volume of a sphere is given by

V = 4/3πr^3

Radius (r) = diameter (d) /2

V = 4/3π(d/2)^3

V = 4/3πd^3/8

V = πd^3 /6

Substituting the value of V into equation 1, we have

V = ( T + mg) /ρg

πd^3 /6 = ( T + mg) /ρg.

Making d the subject of the formula, we have:

πd^3 /6 = (T + mg) /ρg.

d^3 = 6(T + mg) /πρg.

Taking the cube root of both sides

d = [6(T + mg) /πρg]^1/3

Step 3:

Determination of the diameter of the ball. This is illustrated below:

T = 0.029 N

m = 2.5x10^-3Kg

g = 9.81 m/s2

ρ = 1000 kg/m3

d =?

d = [6(T + mg) /πρg]^1/3

d = [6(0.029 + 2.5x10^-3x9.81)/ πx1000x9.81]^1/3

d = 0.022m

Therefore, the diameter of the ball is 0.022m or 2.2cm

6 0
3 years ago
Provide the following information for each of the three types of radiations from naturally radioactive materials. Be sure to inc
scoundrel [369]

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Mass  . . . 4 Atomic Mass Units

Relative penetrating power  . . . low

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<em>Beta radiation</em>:  Particles.  Each beta particle is an electron.

Charge  . . . -1 elementary charge

Mass  . . . 0.00055 AMU

Relative penetrating power  . . . medium

The effect an electric field would have on it . . .  repelled by other negative charges, and attracted toward positive charges.

<em>Gamma radiation</em>:  electromagnetic wave, verrrrry short wave, high frequency

Charge . . . electromagnetic wave, no charge

Mass  . . . electromagnetic wave, no mass

Relative penetrating power  . . . high

The effect an electric field would have on it . . . electromagnetic wave, no effect

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How does velocity describe an objects motion?
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Answer:

Velocity is how fast and in what direction it moves.

Explanation:

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