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3 years ago

What do pressure and temperature determine about a gas

Physics

1 answer:

NikAS [45]3 years ago

8 0

Answer:

With Boyle's law we have that for a constant temperature and gas quantity the pressure of a gas multiplied by its volume is also constant: This means that under the same temperature, two gases with equal quantity of molecules and equal volume must also have the same pressure, as well as that two gases with equal quantity and pressure must have the same volume.

Explanation:

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Match the element with its description.

Nutka1998 [239]

Answer:

1.c

2.b

3.d

4.a

Explanation:

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2 years ago

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Have All existing elements have been discovered

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Answer:

Not not all of the elements have been discovered.

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2 years ago

Question 14 of 30

docker41 [41]

Answer: a.

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A firefighter with a weight of 707 N slides down a vertical pole with an acceleration of 2.79 m/s2, directed downward. (a) What

DedPeter [7]

Answer:

The vertical force acting on the firefighter = 908.27 N

Explanation:

Force: Force of a body is defined as the product of mass and its acceleration. The S.I unit of force is Newton (N)

The vertical force acting on the firefighter = Force due to the weight of the firefighter + force due to acceleration.

Ft = Fw - Fa

Where Ft = The vertical force acting on the firefighter, Fw = Force due to the weight of the firefighter, Fa = force due to acceleration.

Fw = mg

Making m the subject of formula in the equation above

m = Fw/g................... Equation 1

Where m = mass of the firefighter, g = acceleration due to gravity,

Given: Fw = 707 N,

Constant: g = 9.8 m/s²

Substituting these values into eqaution 1

m = 707/9.8

m = 72.14 kg.

But, Fa = ma

Where a = acceleration of the firefighter.

Given: a = 2.79 m/s², 

And m = 72.14 kg

Fa = 72.14 × 2.79

Fa = 201.27 N

Therefore, Ft = 707 + 201.27 = 908.27 N

Ft = 908.27 N

The vertical force acting on the firefighter = 908.27 N

7 0

3 years ago

If the temperature of a volume of ideal gas increases for 100°C to 200°C, what happens to the average kinetic energy of the mole

mina [271]

Answer: $\Delta E=2.0715\times 10^{-21} J$

Explanation:

Given

Temperature of the gas is increased from 100 to 200

Also we know that average kinetic energy of the molecules is

$E=\frac{3}{2}\cdot \frac{R}{N_A}T$

Where

R=Gas constant

$N_A$ =Avogadro's number

T=Temperature in kelvin

$\frac{R}{N_A}=1.381\times 10^{-23}$

So kinetic energy increases by

$\Delta E=\frac{3}{2}\times 1.381\times 10^{-23}\left ( 200-100\right )$

$\Delta E=2.0715\times 10^{-21} J$

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2 years ago