1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ch4aika [34]
3 years ago
7

The instruction booklet for your pressure cooker indicates that its highest setting is 11.1 psi. You know that standard atmosphe

ric pressure is 14.7 psi, so the booklet must mean 11.1 psi above atmospheric pressure.
At what temperature in degrees Celsius will your food cook in this pressure cooker set on "high"?
Chemistry
1 answer:
Jlenok [28]3 years ago
4 0

<u>Answer:</u> The temperature in the pressure cooker set on high is 206.14°C

<u>Explanation:</u>

STP conditions:

Pressure = 14.7 psi

Temperature = 273 K

To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are the initial pressure and temperature of the gas.

P_2\text{ and }T_2 are the final pressure and temperature of the gas.

We are given:

P_1=14.7psi\\T_1=273K\\P_2=(14.7+11.1)psi=25.8psi\\T_2=?

Putting values in above equation, we get:

\frac{14.7psi}{273K}=\frac{25.8psi}{T_2}\\\\T_2=\frac{25.8\times 273}{14.7}=479.14K

Converting the temperature from kelvins to degree Celsius, by using the conversion factor:

T(K)=T(^oC)+273

479.14=T(^oC)+273\\\\T(^oC)=(479.14-273)=206.14^oC

Hence, the temperature in the pressure cooker set on high is 206.14°C

You might be interested in
A student wants to prepare 1.00 L of a 1.00 M solution of NaOH (molar mass 40.00 g/mol). If solid NaOH is available, how would t
Serga [27]

Explanation:

1)

Molarity=\frac{\text{Mass of substance}}{\text{Molar mass of substance}\times \text{Volume of solution(L)}}

Mass of NaOH = m

MOlar mass of NaOH = 40 g/mol

Volume of NaOH solution = 1.00 L

Molarity of the solution= 1.00 M

1.00 M=\frac{m}{40 g/mol\times 1.00 L}

m=1.00 M\times 40 g/mol\times 1.00 L = 40. g

A student can prepare the solution by dissolving the 40. grams of NaOH in is small volume of water and making that whole volume of solution to volume of 1 L.

Upto two significant figures mass should be determined.

2)

M_1V_1=M_2V_2 (dilution equation)

Molarity of the NaOH solution = M_1=2.00 M

Volume of the solution = V_1=?

Molarity of the NaOH solution after dilution = M_2=1.00 M

Volume of NaOH solution after dilution= V_2=1 L

M_1V_1=M_2V_2

V_1=\frac{1.00 M\times 1.00 L}{2.00 M}=0.500 L

A student can prepare NaOH solution of 1.00 M by diluting the 0.500 L of 2.00 M solution of NaOH with water to 1.00 L volume.

Upto three significant figures volume should be determined.

8 0
3 years ago
Be sure to answer all parts. What is the [H3O+] and the pH of a buffer that consists of 0.26 M HNO2 and 0.89 M KNO2? (K, of HNO2
Aleksandr-060686 [28]

Answer : The H_3O^+ ion concentration is, 1.12\times 10^{-3}M and the pH of a buffer is, 2.95

Explanation : Given,

K_a=7.1\times 10^{-4}

Concentration of HNO_2 (weak acid)= 0.26 M

Concentration of KNO_2 (conjugate base or salt)= 0.89 M

First we have to calculate the value of pK_a.

The expression used for the calculation of pK_a is,

pK_a=-\log (K_a)

Now put the value of K_a in this expression, we get:

pK_a=-\log (7.1\times 10^{-4})

pK_a=4-\log (7.1)

pK_a=3.15

Now we have to calculate the pH of the solution.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

pH=pK_a+\log \frac{[KNO_2]}{[HNO_2]}

Now put all the given values in this expression, we get:

pH=3.15+\log (\frac{0.89}{0.26})

pH=2.95

The pH of a buffer is, 2.95

Now we have to calculate the H_3O^+ ion concentration.

pH=-\log [H_3O^+]

2.95=-\log [H_3O^+]

[H_3O^+]=1.12\times 10^{-3}M

The H_3O^+ ion concentration is, 1.12\times 10^{-3}M

4 0
3 years ago
Write a chemical equation for the dissolution of the AgCl precipitate upon the addition of NH,(aq).
Kobotan [32]

Explanation:

White precipitate of silver chloride get dissolves in excess ammonia to formation of complex between silver ions, chloride ions and ammonia molecules.

The chemical reaction is given as:

AgCl(s)+2NH_3(aq)\rightarrow Ag[(NH_3)_2]^+Cl^-(aq)

When 1 mole of silver chloride is added to 2 mole of an aqueous ammonia it form coordination complex of diaaminesilver(I) chloride.

7 0
3 years ago
Ionic equation for reaction of koh(aq) with cucl2(aq)
marishachu [46]

Answer:

2 KOH(aq) + CuCl2(aq) = 2 KCl(s) + Cu(OH)2

Explanation:

8 0
3 years ago
Highly liquid lava forms wide, shield-like mountains. True False
timurjin [86]
This answer is True :)
5 0
3 years ago
Other questions:
  • Why is it preferable to allow cold water to enter at the bottom of a condenser and exit at the top?
    5·1 answer
  • Calculate the mass, in grams, of a single xenon atom (mxe = 131.29 amu ).
    8·1 answer
  • Write a brief account of Ernest Rutherford’s personal and professional life in no more then 150 words
    8·1 answer
  • CH, (g) + 20 (g) → CO(g) + 2H 0(g)
    9·1 answer
  • A kettle of water is at 14.5°C. Its temperature is then raised to 50.0°C by supplying it with 5,680 joules of heat. The specific
    6·2 answers
  • The atomic mass of calcium is calculated by adding the mass (amount) of
    10·2 answers
  • Follow me and get five thanks​
    10·1 answer
  • If we wish to produce 35.4 moles of MgO. How many moles of O2 do we need?​
    15·1 answer
  • C. A 75 lb (34 kg) boy falls out of a tree from a height of 10 ft (3 m). (3 points)
    7·1 answer
  • Can someone help me please?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!