Explanation:
I don't really understand the question
<h3>
Answer:</h3>
Molarity is 0.046 M
<h3>
Explanation:</h3>
We are given;
1.72 mol of LiCl in 37.5 L of solution
We will take the question to be; calculate the molarity of LiCl
Therefore,
we can start by defining molarity as the concentration of a solution in moles per liter.
Molarity of a solution is calculated by dividing the number of moles of solute by the volume of solution.
Molarity = Moles of solute ÷ Volume of the solution
Thus, in this case;
Molarity of LiCl = Moles of LiCl ÷ Volume of the solution
= 1.72 moles ÷ 37.5 L
= 0.0459 M
= 0.046 M
Therefore, the molarity of LiCl solution is 0.046 M
Answer:
1807.24L
Explanation:
Using combined gas law equation:
P1V1/T1 = P2V2/T2
Where;
P1 = pressure on Earth
P2 = Pressure on Mars
V1 = volume on Earth
V2 = volume on Mars
T1 = temperature on Earth
T2 = temperature on Mars
According to the information provided of the balloon in this question;
P1 = 1 atm
P2 = 4.55 torr = 4.55/760 = 0.00599atm
V1 = 14.5L
V2 = ?
T1 = 19°C = 19 + 273 = 292K
T2 = -55°C = -55 + 273 = 218K
Using P1V1/T1 = P2V2/T2
1 × 14.5/292 = 0.00599 × V2/218
14.5/292 = 0.00599V2/218
Cross multiply
14.5 × 218 = 292 × 0.00599V2
3161 = 1.74908V2
V2 = 3161 ÷ 1.74908
V2 = 1807.24L
Answer: Enthalpy of combustion (per mole) of 
is -2657.5 kJ
Explanation:
The chemical equation for the combustion of butane follows:
The equation for the enthalpy change of the above reaction is:
![\Delta H^o_{rxn}=[(8\times \Delta H^o_f_{CO_2(g)})+(10\times \Delta H^o_f_{H_2O(g)})]-[(1\times \Delta H^o_f_{C_4H_{10}(g)})+(4\times \Delta H^o_f_{O_2(g)})]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B%288%5Ctimes%20%5CDelta%20H%5Eo_f_%7BCO_2%28g%29%7D%29%2B%2810%5Ctimes%20%5CDelta%20H%5Eo_f_%7BH_2O%28g%29%7D%29%5D-%5B%281%5Ctimes%20%5CDelta%20H%5Eo_f_%7BC_4H_%7B10%7D%28g%29%7D%29%2B%284%5Ctimes%20%5CDelta%20H%5Eo_f_%7BO_2%28g%29%7D%29%5D)
We are given:
Putting values in above equation, we get:
![\Delta H^o_{rxn}=[(8\times -393.5)+(10\times -241.82)]-[(2\times -125.6)+(4\times 0)]\\\\\Delta H^o_{rxn}=-5315kJ](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B%288%5Ctimes%20-393.5%29%2B%2810%5Ctimes%20-241.82%29%5D-%5B%282%5Ctimes%20-125.6%29%2B%284%5Ctimes%200%29%5D%5C%5C%5C%5C%5CDelta%20H%5Eo_%7Brxn%7D%3D-5315kJ)
Enthalpy of combustion (per mole) of is -2657.5 kJ
<span>Definition of Metallurgy-The branch of science and technology concerned with the properties of metals and their production and purification.</span>
