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3 years ago

What's an example of gravitational force?

2 answers:

7 0

An example of gravational force would be an apple falling from a tree. Basically, when the stem breaks, the apple falls towards the center of the earth.

Inga [223]3 years ago

6 0

What goes up must come down. Throwing something that eventually lands .

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There are around muscles in the human body 640 250 100

Gwar [14]

There are 640 muscles in the human body

6 0

4 years ago

Oxygen gas, generated by the reaction 2 KClO 3 ---- 2 KCl + 3 O 2 , is collected over water at 27 C in a 2.00 L vessel at a tota

laila [671]

Answer:

The moles of KClO3 = 0.052 moles

Explanation:

Step 1: Calculate the pressure of oxygen gas

The oxygen has a total pressure (including water vapour) of 760 mmHg

The pressure of Oxygen = (760 - 26) mmHg

= 734 mmHg of water vapor

Step 2: Calculate the no of moles of oxygen

Using Ideal gas equation

P V = n R T

P = pressure of oxygen in N/m2 ( you should convert 734 mmHg to pascal or N/m2) = 97,858.6 N/m2 or pas

V = 2 litres = 0.002 m3

R = gas constant = 8.31

T= 27oC = 300 K

Applying this equation P V = n R T

97,858.6 x 0.002 = n x 8.31 x 300

n = 0.0785 mol of Oxygen

From the balanced equation

2 KClO 3 ---- 2 KCl + 3 O 2

3 moles of oxygen is produced from 2 moles KClO3

so 0.0785 mole of oxygen will be produced from x

x = (0.0785 x 2 ) / 3

x = 0.052 moles of KClO3

5 0

4 years ago

Using the atomic masses and relative abundance of the isotopes of nitrogen given below, determine the average atomic mass of nit

masha68 [24]

To calculate the average mass of the element, we take the summation of the product of the isotope mass and the percent abundance. In this case, it is 0.9963 * 14.003 amu + 0.0037* 15.00 amu. This is equal to an average mass of 14.00668889 amu.

8 0

3 years ago

____CO + ____H2 ----> ____C8H18 +____H2O

masha68 [24]

8CO+9H2 —> 1 C8H18+9H2O

3 0

3 years ago

At 46°C a sample of ammonia gas exerts a pressure of 5.3 atm. What is the pressure when the volume of the gas is reduced to one-

snow_lady [41]

Hello there!

As you may know, pressure and volume have an inverse relationship. This means that as pressure increases, volume decreases (and as volume increases, pressure decreases).

In this problem, the volume of the gas is reduced to 0.250 its original value. This means that the pressure should be higher than it was originally.

We can use Boyle's Law to solve this problem, seeing that temperature is kept constant.

P1V1 = P2V2

Let's rearrange this equation to isolate the variable we need, P2.

P1V1

------- = P2

That's better! Now that we have that down, let's plug in the numbers we were given.

(5.3atm) * (V1)

-------------------- = P2

0.25(V1)

We can get rid of V1, as the number would be equal to 1 (anything divided by itself is equal to 1).

5.3atm

---------- = 21.2 atm

0.25L

Now, while the number is significantly higher, this is quite reasonable.

Let's plug it in and see if we get what we should:

5.3(V1) = (0.25V1)(21.2)

--------

0.25V1

21.2 atm = 21.2 atm

Seems right to me!

Feel free to comment if you need any more help. :)

5 0

4 years ago