Question

2al2o3 yields to 4al + 3o2 .. how many miles of oxygen are produced from the decomposition of 1.26 mil of Al2O3?

Answer 1

Answer:

$\large \boxed{\text{2.52 mol Al}}$

Explanation:

           2Al₂O₃ ⟶ 4Al +3O₂

n/mol:    1.26

The molar ratio is 4 mol Al:2 mol Al₂O₃.

$\text{Moles of Al} = \text{1.26 mol Al _{2} O}_{3} \times \dfrac{\text{4 mol Al}}{\text{2 mol Al _{2} O}_{3}}= \textbf{2.52 mol Al}\\\\\text{The reaction produces \large \boxed{\textbf{2.52 mol Al}} }$