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Sergeu [11.5K]
3 years ago
14

a 25 newton force applied on an object moves it 50 meters. the angle between the force and displacement is 40.0°. what is the va

lue of work being done on the object? a. 0 joules b. 9.6 × 102 joules c. 1.2 × 103 joules d. -9.6 × 102 joules e. -1.2 × 103 joules
Physics
1 answer:
LiRa [457]3 years ago
3 0
Work = force × distance × cos(angle)

work = (25)(50)(cos (40))

work = 957.56 Joules

= 9.6x10^2 Joules
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A bike travels at 7.5 m/s along a straight road, whereas a car travels at 10.0 m/s along the same road and in the same direction
Ilya [14]

Answer:

t = 8.3 s

Explanation:

As we know that

velocity of bike = 7.5 m/s

velocity of car is 10 m/s

deceleration of car is 0.75 m/s^2

part a)

velocity of bike with respect to car is given as

v_r = 7.5 - 10 = -2.5 m/s

acceleration of bike with respect to car is given as

a_r = 0 - (-0.75) = 0.75 m/s^2

now the distance of the bike with respect to car is given as

d = v_i t + \frac{1}{2}at^2

5 = (-2.5) t + \frac{1}{2}(0.75)t^2

t = 8.3 s

Part b)

3 0
3 years ago
Which of these actions will increase friction? Select three options. Scratching a surface to make it rougher polishing a surface
k0ka [10]

Answer:

scratching a surface to make it rougher

increasing the size of a flying object

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Explanation:

5 0
3 years ago
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Establishing a potential difference The deflection plates in an oscilloscope are 10 cm by 2 cm with a gap distance of 1 mm. A 10
Nezavi [6.7K]

Answer:

t = 23.9nS

Explanation:

given :

Area A= 10 cm by 2 cm => 2 x 10^-2m x 10 x 10^-2m

distance d= 1mm=> 0.001

resistor R= 975 ohm

Capacitance can be calculated through the following formula,

C = (ε0  x A )/d

C = (8.85 x 10^-12 x (2 x 10^-2 x 10 x 10^-2))/0.001

C = 17.7 x 10^-12    (pico 'p' = 10^-12)

C = 17.7pF

the voltage between two plates is related to time, There we use the following formula of the final voltage

Vc = Vx (1-e^-(t/CR))  

75 = 100 x (1-e^-(t/CR))

75/100 = (1-e^-(t/CR))

.75 = (1-e^-(t/CR))

.75 -1 = -e^-(t/CR)

-0.25 = -e^-(t/CR)  --->(cancelling out the negative sign)

e^-(t/CR) = 0.25

in order to remove the exponent, take logs on both sides  

-t/CR = ln (0.25)

t/CR = -ln(0.25)

t = -CR x ln (0.25)

t = -(17.7 x 10^-12 x 975) x (-1.38629)

t = 23.9 x 10^{-9  

t = 23.9ns

Thus, it took 23.9ns  for the potential difference between the deflection plates to reach 75 volts

6 0
3 years ago
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Who would win Goku Mastered Ultra Instinct 3 Kaioken X20 (And can withstand the power strain) or Shaggy using 10% of his power?
alexgriva [62]

Answer:

goku

Explanation:

i just guessed

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3 years ago
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the magnitude of the magnetic field at point p for a certain electromagnetic wave is 2.21. What is the magnitude of the elctic f
vesna_86 [32]

Answer:

6.63\times 10^8\ N/C

Explanation:

Given that,

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We need to find the magnitude of the electric field. Let it is E. So,

\dfrac{E}{B}=c\\\\E=Bc

Put all the values,

E=2.21\times 3\times 10^8\\\\=6.63\times 10^8\ N/C

So, the magnitude of the electric field is equal to 6.63\times 10^8\ N/C.

7 0
2 years ago
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