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Firdavs [7]
3 years ago
14

what changes can be made to the transfer of energy as heat to a heat engine in order to increase the amount of work done by the

engine
Physics
1 answer:
Stella [2.4K]3 years ago
5 0

Idk tbh you tell me??

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The car starts from a room with a constant acceleration of 5 ms-2. What path will it pass in 6 seconds and what speed will it re
Kobotan [32]

Answer: The speed will be  30 m/s .

Explanation:

Given: Initial velocity of the car: u = 0 m/s

Constant Acceleration: a = 5 m/s²

Time: t= 6 seconds

To find: Final velocity(v)

Formula:  v = u+at

Substitute values in the formula, we get

v=  0+(5)(6) m/s

⇒ v= 30 m/s

i.e. Final velocity = 30 m/s

Hence, the speed will be 30 m/s .

4 0
3 years ago
Can someone answer and explain these questions?
Andru [333]

Answer:

oh that looks hard but sorry im not good at math ether so sorry i couldnt help

Explanation:

7 0
2 years ago
A 1200 kg car is brought from 25 m/s to 10m/s over a time period of 5 seconds. Determine the force experienced by the car
aleksklad [387]
It's simple.
We know force is the rate of change in momentum.
So F=(mv-mu)/t or F=m(v-u)/t
=1200*(25-10)/5=3600N
7 0
3 years ago
I need help on this question
raketka [301]

Answer:

there are 5 hydrogen atoms in that formula

3 0
3 years ago
Read 2 more answers
The voltage across a 5-uF capacitor is: v (t )equals 10 cos open parentheses 6000 t close parentheses space straight V. What is
mamaluj [8]

Answer:

- 0.3sin6000t A

Explanation:

Voltage, v = 10 cos 6000t V

Capacitance = 5-uF

Current flowing through, i(t)

i(t) = c * d/dt (V)

c = 5-uF = 5 * 10^-6 F

i(t) = (5 * 10^-6) * d/dt(10 cos 6000t)

d/dt(10 cos 6000t) = (10 * 6000) * (-sin 6000t)

Hence,

i(t) = (5*10^-6) * (10*6000) * (-sin 6000t)

i(t) = 5*10^-6 * 6*10^4 * - sin6000t

i(t) = 30 * 10^-2 * - sin6000t

i(t) = 0.3*-sin6000t

i(t) = - 0.3sin6000t Ampere

4 0
3 years ago
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