First, determine the mass of the object by dividing its weight on Earth by 9.8 m/s² as shown below,
m = 250 N / 9.8 m/s² = 25.51 kg
Then, multiply the obtained mass by the acceleration due to gravity (g) on Pluto.
W (in Pluto) = (25.51 kg) x (0.61 m/s²) = 15.56 N
Therefore, the object will only weigh 15.56 N.
The products of a chemical reaction are the substances that are changed and the chemicals on the right side of a chemical equation. The correct options are B and C.
<h3>What is chemical reaction?</h3>
The chemical reaction is the reaction between two reactants which led to the formation of products.
The products are substances which forms after reaction. The reactants are the substances which are original materials.
The reactants lie on the left side and products lie on the right side of the reaction.
Thus, the correct options are B and C.
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The radial velocity method preferentially detects large planets close to the central star
- what is the Radial velocity:
The radial velocity technique is able to detect planets around low-mass stars, such as M-type (red dwarf) stars.
This is due to the fact that low mass stars are more affected by the gravitational tug of planets.
When a planet orbits around a star, the star wobbles a little.
From this, we can determine the mass of the planet and its distance from the star.
hence we can say that,
option D is correct.
The radial velocity method preferentially detects large planets close to the central star
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Answer:
-6N
Explanation:
The force to the east is acting in the positive x-direction therefore it is positive. The force to the east is in the negative x-direction therefore it is negative. The net force is just the sum of the two so 3-9=-6
In order to accelerate the dragster at a speed

, its engine must do a work equal to the increase in kinetic energy of the dragster. Since it starts from rest, the initial kinetic energy is zero, so the work done by the engine to accelerate the dragster to 100 m/s is

however, we must take into account also the fact that there is a frictional force doing work against the dragster, and the work done by the frictional force is:

and the sign is negative because the frictional force acts against the direction of motion of the dragster.
This means that the total work done by the dragster engine is equal to the work done to accelerate the dragster plus the energy lost because of the frictional force, which is

:

So, the power delivered by the engine is the total work divided by the time, t=7.30 s:

And since 1 horsepower is equal to 746 W, we can rewrite the power as