Question

A helium-filled balloon occupies a volume of 15 cubic meters at sea level. the balloon is released and raises to a point in the atmosphere where the pressure is .75 atm. what is its volume if the temperature remains the same?

Answer 1

According to Boyle’s law, For a fixed amount of an ideal gas kept at a fixed temperature, P (pressure) and V (volume) are inversely proportional.

Therefore,

$P_{1} V_{1} =P_{2} V_{2}$

Given $P_{1} = 1 atm$ , $V_{1} = 15 \ cubic \ meter$ and $P_{2} = 0.75\ atm$.

Thus,

$V_{2} = \frac{P_{1}\times V_{1} }{ P_{2} } = \frac{1\times 15}{0.75} =20 m^3$