Explanation:
perturbateur ( le temps, le lieu, les personnages[description], la victime, l'enqueteur )
les peripeties
le denouement
Answer:
0.1 nm
Explanation
Potential deference of the electron is given as V =150 V
Mass of electron ![m=9.1\times 10^{-31}](https://tex.z-dn.net/?f=m%3D9.1%5Ctimes%2010%5E%7B-31%7D)
Let the velocity of electron = v
Charge on the electron ![=1.6\times 10^{-19}C](https://tex.z-dn.net/?f=%3D1.6%5Ctimes%2010%5E%7B-19%7DC)
plank's constant h =![6.67\times 10^{-34}](https://tex.z-dn.net/?f=6.67%5Ctimes%2010%5E%7B-34%7D)
According to energy conservation ![eV =\frac{1}{2}mv^2](https://tex.z-dn.net/?f=eV%20%3D%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
![v=\sqrt{\frac{2eV}{M}}=\sqrt{\frac{2\times 1.6\times 10^{-19}\times 150}{9.1\times 10^{-31}}}=7.2627\times 10^{-6}m/sec](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B%5Cfrac%7B2eV%7D%7BM%7D%7D%3D%5Csqrt%7B%5Cfrac%7B2%5Ctimes%201.6%5Ctimes%2010%5E%7B-19%7D%5Ctimes%20150%7D%7B9.1%5Ctimes%2010%5E%7B-31%7D%7D%7D%3D7.2627%5Ctimes%2010%5E%7B-6%7Dm%2Fsec)
Now we know that De Broglie wavelength ![\lambda =\frac{h}{mv}=\frac{6.67\times 10^{-34}}{9.1\times 10^{-31}\times 7.2627\times10^6 }=0.100\times 10^{-9}m=0.1nm](https://tex.z-dn.net/?f=%5Clambda%20%3D%5Cfrac%7Bh%7D%7Bmv%7D%3D%5Cfrac%7B6.67%5Ctimes%2010%5E%7B-34%7D%7D%7B9.1%5Ctimes%2010%5E%7B-31%7D%5Ctimes%207.2627%5Ctimes10%5E6%20%7D%3D0.100%5Ctimes%2010%5E%7B-9%7Dm%3D0.1nm)
Answer:
I think it is( More expensive than immature technologies) I took engineering class and this question is still quite tricky.
Explanation:
Answer:
goodman = 0.694
life of beam = 211597
Explanation:
alternating stress = 48 kpsi
mean stress = 24 kpsi
ultimate strength = 100 kpsi
endurance limit = 40 kpsi
goodman:
= ![\frac{mean stress}{ultimate stress} +\frac{alternating stress}{endurance limit} =\frac{1}{N}](https://tex.z-dn.net/?f=%5Cfrac%7Bmean%20stress%7D%7Bultimate%20stress%7D%20%2B%5Cfrac%7Balternating%20stress%7D%7Bendurance%20limit%7D%20%3D%5Cfrac%7B1%7D%7BN%7D)
= ![\frac{24}{100} +\frac{48}{40} =\frac{1}{N}](https://tex.z-dn.net/?f=%5Cfrac%7B24%7D%7B100%7D%20%2B%5Cfrac%7B48%7D%7B40%7D%20%3D%5Cfrac%7B1%7D%7BN%7D)
= 0.24 + 1.2 = ![\frac{1}{N}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BN%7D)
N = 1/1.44
N = 0.694
2. check attachment for diagram
Log(N)-3/3 = log90 - log48/log90 - log40
Log(N)-3/3 = 0.77517
Log N = 5.325509
N = 10^(5.325509)
N = 211597