Answer:
(C) passive state.
Explanation:
The earth pressure is the pressure exerted by the soil on the shoring system. They are three types of earth pressure which are:
a) Rest state: In this state, the retaining wall is stationary, this makes the lateral stress to be zero.
b) Active state: In this state, the wall moves away from the back fill, this leads to an internal resistance. Hence the active earth pressure is less than earth pressure at rest
c) Passive state: In this state the wall is pushed towards the back fill, this leads to shearing resistance. Hence, the passive earth pressure is greater than earth pressure at rest
Answer:
a. The coefficient of power = 2.6364
b. The rate of heat absorption from the outside air is 1.96368kW
Explanation:
Given
First we need to get the enthalpy of R-34a.
When T = 35°C and P = 800kPa;
h1 = 271.24kj/kg
When x2 = 0 and P = 800kPa;
h1 = 95.48kj/kg
To calculate the COP, first we need to calculate the energy balance.
This is given as
Q = m(h1 - h2)
Where m = 0.018kg
Q = 0.018(271.24 - 95.48)
Q = 3.16368Kw
COP is then calculated as Q/W
Where W = Power consumption of the compressor = 1.2kW
COP = 3.16368Kw/1.2Kw
COP = 2.6364
Hence, the coefficient of power = 2.6364
b. The rate of heat absorption from the outside air is calculated as ∆Heat Rate
∆Heat Rate = Q - W
Where Q = Energy Balance = 3.16368Kw
W = Power consumption of the compressor = 1.2kW
∆Heat Rate = 3.16368Kw - 1.2kW
∆Heat Rate = 1.96368kW
Hence, The rate of heat absorption from the outside air is 1.96368kW