Answer: hello your question is incomplete below is the complete question
answer:
N010 GO2 X7.0 Y2.0 15.0 J2.0 ( option 1 )
Explanation:
Given that the NC machining has to be moved from point ( 5,4 ) to point ( 7,2 ) along a circular path
GO2 = circular interpolation in a clockwise path
G91 = incremental dimension
<em>hence the correct option is </em>:
N010 GO2 X7.0 Y2.0 15.0 J2.0
Answer:
(b)False
Explanation:
Given:
Prandtl number(Pr) =1000.
We know that 
Where 
is the molecular diffusivity of momentum
is the molecular diffusivity of heat.
Prandtl number(Pr) can also be defined as
Where 
is the hydrodynamic boundary layer thickness and 
is the thermal boundary layer thickness.
So if Pr>1 then hydrodynamic boundary layer thickness will be greater than thermal boundary layer thickness.
In given question Pr>1 so hydrodynamic boundary layer thickness will be greater than thermal boundary layer thickness.
So hydrodynamic layer will be thicker than the thermal boundary layer.
Answer:
if ur mad you may drive faster if ur sad u may drive slower due to the amount of adrenaline and dopamine levels in your body in that given moment
Explanation:
Answer:
public static int average(int j, int k) {
return (int)(( (long)(i) + (long)(j) ) /2 );
}
Explanation:
The above code returns the average of two integer variables
Line 1 of the code declares a method along with 2 variables
Method declared: average of integer data type
Variables: j and k of type integer, respectively
Line 2 calculates the average of the two variables and returns the value of the average.
The first of two integers to average is j
The second of two integers to average is k
The last parameter ensures average using (j+k)/2
Below is the program to separate odd and even numbers
<u>Explanation</u>:
<u>L1:</u>
mov ah,00
mov al,[BX]
mov dl,al
div dh
cmp ah,00
je EVEN1
mov [DI],dl
add OddAdd,dl
INC DI
INC BX
Loop L1
jmp CAL
<u>EVEN1:</u>
mov [SI],dl
add Even Add,dl
INC SI
INC BX
Loop L1
<u>CAL: </u>
mov ax,0000
mov bx,0000
mov al,OddAdd
mov bl,EvenAdd
MOV ax,4C00h
int 21h
end
The above program separates odd and even numbers from the array using 8086 microprocessor. It has odd numbers in 2000h and even numbers in 3000h.
