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inysia [295]
3 years ago
5

Please choose a specific type of stability or control surface (e.g., a canard) and explain how it is used, what it is used for,

and the pros and cons of the device or system.
Engineering
1 answer:
Thepotemich [5.8K]3 years ago
3 0

Answer:

small forewing

<u>pro</u> : Can be used in place of tail plane configuration

<u>con</u> : Can be very complex and difficult to use

Explanation:

A canard is generally used to provide some form of stability to an unstable or semi stable system.

An example of a Canard is a small forewing placed in an aircraft that will help stabilize the aircraft when in motion( in air ). because an airplane is generally an unstable system on its own

<u>pro </u>: Can be used in place of tail plane configuration

<u>con</u> : Can be very complex and difficult to use

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Alchen [17]

Answer:

  d. all of these

Explanation:

Electrostatic discharge will generally produce excess voltage in a local area that results in excessive current and excessive heat. It will blast a crater in an MOS device, or melt bond wires, or cause damage of other sorts. In short, MOS devices are subject to damage from "all of these."

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Choose the correct word or phrase to complete the sentence to explain human intervention in a machine system.
maksim [4K]

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A cartridge electrical heater is shaped as a cylinder of length L=200mm and outer diameter D=20 mm. Under normal operating condi
lara31 [8.8K]

Answer:

T(water)=50.32℃

T(air)=3052.6℃

Explanation:

Hello!

To solve this problem we must use the equation that defines the transfer of heat by convection, which consists of the transport of heat through fluids in this case water and air.

The equation is as follows!

Q=ha(Ts-T\alpha )

Q = heat

h = heat transfer coefficient

Ts = surface temperature

T = fluid temperature

a = heat transfer area

The surface area of ​​a cylinder is calculated as follows

a=\pi D(\frac{D}{2} +L)

Where

D=diameter=20mm=0.02m

L=leght=200mm)0.2m

solving

a=\pi (0.02)(\frac{0.02}{2} +0.2)=0.01319m^2

For water

Q=2Kw=2000W

h=5000W/m2K

a=0.01319m^2

Tα=20C

Q=ha(Ts-T\alpha )

solving for ts

Ts=T\alpha +\frac{Q}{ha}

Ts=20+\frac{2000}{(0.01319)(5000)} =50.32C

for air

Q=2Kw=2000W

h=50W/m2K

a=0.01319m^2

Tα=20C

Ts=20+\frac{2000}{(0.01319)(50)}=3052.6C

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3 years ago
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3 years ago
Please answer question #2
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