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jolli1 [7]
3 years ago
6

A piece of aluminum wire is 500 ft long and has a diameter of 0.03 inches. What is the resistance of the piece of wire?​

Engineering
1 answer:
dexar [7]3 years ago
5 0

Answer:

8.85 Ω

Explanation:

Resistance of a wire is:

R = ρL/A

where ρ is resistivity of the material,

L is the length of the wire,

and A is the cross sectional area.

For a round wire, A = πr² = ¼πd².

For aluminum, ρ is 2.65×10⁻⁸ Ωm, or 8.69×10⁻⁸ Ωft.

Given L = 500 ft and d = 0.03 in = 0.0025 ft:

R = (8.69×10⁻⁸ Ωft) (500 ft) / (¼π (0.0025 ft)²)

R = 8.85 Ω

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A gas expands in a piston-cylinder assembly from p1 = 8 bar, V1 = 0.02 m3 to p2 = 2 bar. The relation between pressure and volum
Charra [1.4K]

Answer:

The heat transfer is 29.75 kJ

Explanation:

The process is a polytropic expansion process

General polytropic expansion process is given by PV^n = constant

Comparing PV^n = constant with PV^1.2 = constant

n = 1.2

(V2/V1)^n = P1/P2

(V2/0.02)^1.2 = 8/2

V2/0.02 = 4^(1/1.2)

V2 = 0.02 × 3.2 = 0.064 m^3

W = (P2V2 - P1V1)/1-n

P1 = 8 bar = 8×100 = 800 kPa

P2 = 2 bar = 2×100 = 200 kPa

V1 = 0.02 m^3

V2 = 0.064 m^3

1 - n = 1 - 1.2 = -0.2

W = (200×0.064 - 800×0.02)/-0.2 = -3.2/-0.2 = 16 kJ

∆U = 55 kJ/kg × 0.25 kg = 13.75 kJ

Heat transfer (Q) = ∆U + W = 13.75 + 16 = 29.75 kJ

7 0
3 years ago
A series of three direct shear tests has been conducted on a certain saturated soil. Each test was performed on a 2.375-inch dia
Pachacha [2.7K]

Answer:

Go to explaination for the details of the answer.

Explanation:

Angle of friction (friction angle) is a measure of the ability of a unit of rock or soil to withstand a shear stress. It is the angle (φ), measured between the normal force (N) and resultant force (R), that is attained when failure just occurs in response to a shearing stress (S).

The cohesion intercept is a used when we want to describe the shear strength soils. The definition is mainly derived from the Mohr-Coulomb failure criterion and it is used to describe the non-frictional part of the shear resistance which is independent of the normal stress.

Please check attachment to Determine the friction angle and cohesion intercept.

8 0
3 years ago
You have been assigned the task of reviewing the relief scenarios for a specific chemical reactor in your plant. You are current
postnew [5]

Answer:

D=0.016m

Explanation:

From the question we are told that:

Discharge Rate F_r=0.5kgls

Pressure P=15Kpa

Temperature T=25=>298K

Ambient pressure is 1 atm.

Generally the equation for Density is mathematically given by

\rho=\frac{PM}{RT}

\rho=\frac{15*10^5*28.0134*10^{-3}}{8.314*298}

\rho=16.958kg/m^2

Generally the equation for Flow rate is mathematically given by

F_r=\mu A\sqrt{Q \rho P(\frac{2}{Q+1})^{\frac{Q+1}{Q-1}}}

Where

Q=Heat coefficient\ ratio\ of\ Nitrogen

Q=1.4

\mu= Discharge\ coefficient

\mu=0.68

Therefore

0.5=0.68 A\sqrt{1.4 16.958 15*10^{5}(\frac{2}{1.4+1})^{\frac{1.4+1}{1.4-1}}}

A=2.129*10^{-4}

Where

A=\frac{\pi}{4}D^2

\frac{\pi}{4}D^2=2.129*10^{-4}

D=0.016m

8 0
3 years ago
If a PPE doesn’t fit properly do you keep wearing them
masha68 [24]
What is that lol? Ensuring
7 0
3 years ago
Read 2 more answers
A 3.0-m wide rectangular asphalt channel discharges 33.84 m^3/s of water with a depth of 2.0 m. What is the head loss in 100 m l
BaLLatris [955]

Answer:

Head loss in 100 m length equals 1.00 m.

Explanation:

The head loss in an open channel is calculated using manning's equation as follows

Q=\frac{1}{n}\frac{A^{5/3}}{P^{2/3}}S_{f}^{1/2}

For a asphalt rectangular channel we have

Area of flow = 3.0\times 2.0 = 6m^{2}

Wetted Perimeter = 3.0+2\times 2.0=7.0m

manning's roughness coefficient = 0.016

Applying values in the above equation we get

33.84=\frac{1}{0.016}\times \frac{6^{5/3}}{7^{2/3}}S_{f}^{1/2}\\\\\therefore S^{1/2}_{f}=0.1\\\\\therefore S_{f}=0.01

Now we know that

S_{f}=\frac{H_{L}}{L}\\\\\therefore H_{l}=0.01\times 100m=1.00m

8 0
3 years ago
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