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jolli1 [7]
3 years ago
6

A piece of aluminum wire is 500 ft long and has a diameter of 0.03 inches. What is the resistance of the piece of wire?​

Engineering
1 answer:
dexar [7]3 years ago
5 0

Answer:

8.85 Ω

Explanation:

Resistance of a wire is:

R = ρL/A

where ρ is resistivity of the material,

L is the length of the wire,

and A is the cross sectional area.

For a round wire, A = πr² = ¼πd².

For aluminum, ρ is 2.65×10⁻⁸ Ωm, or 8.69×10⁻⁸ Ωft.

Given L = 500 ft and d = 0.03 in = 0.0025 ft:

R = (8.69×10⁻⁸ Ωft) (500 ft) / (¼π (0.0025 ft)²)

R = 8.85 Ω

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Answer:

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Explanation:

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(i'm not sure if this is what your question is asking for so i just made my best guess)

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2 years ago
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3 years ago
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Sergeeva-Olga [200]

Answer:

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Explanation:

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4 0
3 years ago
A shunt regulator utilizing a zener diode with an incremental resistance of 8 ohm is fed through an 82-Ohm resistor. If the raw
spayn [35]

Answer:

\triangle V_0=0.08V

Explanation:

From the question we are told that:

Incremental resistance  R=8ohms

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Generally the equation for  voltage rate of change is mathematically given by

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7 0
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