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11Alexandr11 [23.1K]
3 years ago
5

Not needed anymore! Sorry for the inconvenience.

Chemistry
1 answer:
notka56 [123]3 years ago
6 0

Answer:

Explanation:

What?

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We are given with
M1 = 1.00 M

M2 = 0.300 M
V2 = 2.00 L

We are asked to get V1

Using material balance
M1 V1 = M2 V2
Substituting the given values
1.00 V1 = 0.300 M (2.00 L)
V1 = 0.600 L or 600 mL
THe volume needed is 600 mL<span />
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What is the pH of a 6.7 x 10^−5 M H+ solution?
lyudmila [28]

Answer:

pH = 4.17

Explanation:

According to the molar concentration you stated, pH of the solution is: 4.17

Remember that pH = - log [H⁺]

and [H⁺] = 10^-pH

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Calculate the volume of 0.250 M H2SO4 that contains 0.00255 mol H2SO4.
antoniya [11.8K]

Answer:

0.0102 L or 10.2 mL

Explanation:

From the question given above, the following data were obtained:

Molarity = 0.250 M

Mole = 0.00255 mole

Volume =?

Molarity is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is expressed as:

Molarity = mole / Volume

With the above formula, we can obtain the volume as follow:

Molarity = 0.250 M

Mole = 0.00255 mole

Volume =?

Molarity = mole / Volume

0.250 = 0.00255 / volume

Cross multiply

0.250 × volume = 0.00255

Divide both side by 0.250

Volume = 0.00255 / 0.250

Volume = 0.0102 L

Covert 0.0102 L to mL.

1 L = 1000 mL

Therefore,

0.0102 L = 0.0102 L × 1000 / 1 L

0.0102 L = 10.2 mL

Thus, the volume is 0.0102 L or 10.2 mL

4 0
2 years ago
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