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11Alexandr11 [23.1K]
3 years ago
5

Not needed anymore! Sorry for the inconvenience.

Chemistry
1 answer:
notka56 [123]3 years ago
6 0

Answer:

Explanation:

What?

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Commercial grade fuming nitric acid contains about 90.0% HNO3 by mass with a density of 1.50 g/mL, calculate the molarity of the
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Answer:

Since molarity is defined as moles of solute per liter of solution, we need to find the number of moles of nitric acid, and the volume of solution.

molar mass of nitric acid (HNO3) = 1 + 14 + (3x16) = 15 + 48 = 63 g/mole

1.50 g/ml x 1000 ml = 1500 g/liter

1500 g/liter x 0.90 = 1350 g/liter of pure HNO3 (the 0.9 is to correct for the fact that it is 90% pure)

1350 g/liter x 1 mole/63 g = 21.43 moles/liter = 21 Molar HNO3

= 21 Molar of HNO3

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The _______ are found on the left side of the arrow in a chemical reaction.
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The reactants are found on the left side, the products are found on the right side.
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Propane(C3H8) combusts with oxygen gas. If you start with 15 grams of Propane, how many grams of carbon dioxide will be produced
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<em>mC₃H₈: 44 g/mol</em>
<em>mCO₂: 44 g/mol</em>
---------------------

C₃H₈ + 5O₂ ----> 3CO₂ + 4H₂O
44g                    (44·3)g


44g C₃H₈ ------ 132g CO₂
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X = (15×132)/44
<u>X = 45g CO₂
</u>

_____
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325.82 g/mol

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