Answer:
Since molarity is defined as moles of solute per liter of solution, we need to find the number of moles of nitric acid, and the volume of solution.
molar mass of nitric acid (HNO3) = 1 + 14 + (3x16) = 15 + 48 = 63 g/mole
1.50 g/ml x 1000 ml = 1500 g/liter
1500 g/liter x 0.90 = 1350 g/liter of pure HNO3 (the 0.9 is to correct for the fact that it is 90% pure)
1350 g/liter x 1 mole/63 g = 21.43 moles/liter = 21 Molar HNO3
= 21 Molar of HNO3
The reactants are found on the left side, the products are found on the right side.
<em>mC₃H₈: 44 g/mol</em>
<em>mCO₂: 44 g/mol</em>
---------------------
C₃H₈ + 5O₂ ----> 3CO₂ + 4H₂O
44g (44·3)g
44g C₃H₈ ------ 132g CO₂
15g C₃H₈ ------ X
X = (15×132)/44
<u>X = 45g CO₂
</u>
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