If you increase the distance by double the work will _____________
1 answer:
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Answer:
(a). The height of the cliff is 41.67 m.
(b). The maximum height of the ball is 41.67 m
(c). The ball's impact speed is 16.52 m/s.
Explanation:
Given that,
Speed = 33 m/s
Angle = 60°
Time = 3.0 sec
(a). We need to calculate the height of the cliff
Using equation of motion
Put the value into the formula
(b). We need to calculate the maximum height of the ball
Using formula of height
Put the value into the formula
(c). We need to calculate the vertical component of velocity of ball
Using equation of motion
Put the value into the formula
We need to calculate the horizontal component of velocity of ball
Using formula of velocity
Put the value into the formula
We need to calculate the ball's impact speed
Using formula of velocity
Put the value into the formula
Hence, (a). The height of the cliff is 41.67 m.
(b). The maximum height of the ball is 41.67 m
(c). The ball's impact speed is 16.52 m/s.
Answer:
The final temperature of both objects is 400 K
Explanation:
The quantity of heat transferred per unit mass is given by;
Q = cΔT
where;
c is the specific heat capacity
ΔT is the change in temperature
The heat transferred by the object A per unit mass is given by;
Q(A) = caΔT
where;
ca is the specific heat capacity of object A
The heat transferred by the object B per unit mass is given by;
Q(B) = cbΔT
where;
cb is the specific heat capacity of object B
The heat lost by object B is equal to heat gained by object A
Q(A) = -Q(B)
But heat capacity of object B is twice that of object A
The final temperature of the two objects is given by
But heat capacity of object B is twice that of object A
Therefore, the final temperature of both objects is 400 K.