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Anettt [7]
3 years ago
5

Two girl scouts are sitting in a large canoe on a still lake while at summer camp. the canoe happens to be oriented with the fro

nt of the canoe pointing due north. one of the girls is at the front of the canoe and the other is at the back of the canoe. the girl at the front walks to sit next to her friend at the back and sits down. what effect does this event have on the canoe?
Physics
1 answer:
MrRissso [65]3 years ago
7 0
That it's more puashe on the back of the canoe and that effects the back of the canoe to fall back
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An object has a position given by r = [2.0 m + (5.00 m/s)t] i^ + [3.0m−(2.00 m/s2)t2] j^, where all quantities are in SI units.
makkiz [27]

Answer:

Acceleration of the object is 4\ m/s^2.

Explanation:

It is given that, the position of the object is given by :

r=[2\ m+(5\ m/s)t]i+[3\ m-(2\ m/s^2)t^2]j

Velocity of the object, v=\dfrac{dr}{dt}

Acceleration of the object is given by :

a=\dfrac{d^2r}{dt^2}

a=\dfrac{d^2}{dt^2}([2\ m+(5\ m/s)t]i+[3\ m-(2\ m/s^2)t^2]j)

Using the property of differentiation, we get :

a=\dfrac{d^2r}{dt^2}=-4\ m/s^2

So, the magnitude of the acceleration of the object at time t = 2.00 s is 4\ m/s^2. Hence, this is the required solution.

5 0
3 years ago
A Carnot heat engine has an efficiency of 0.400. If it operates between a deep lake with a constant temperature of 298.0k and a
tatuchka [14]

Answer:

496.7 K

Explanation:

The efficiency of a Carnot engine is given by the equation:

\eta = 1 - \frac{T_H}{T_L}

where:

T_H is the temperature of the hot reservoir

T_C is the temperature of the cold reservoir

For the engine in the problem, we know that

\eta = 0.400 is the efficiency

T_C = 298.0 K is the temperature of the cold reservoir

Solving for T_H, we find:

\frac{T_C}{T_H}=1-\eta\\T_H = \frac{T_C}{1-\eta} =\frac{298.0}{1-0.400}=496.7 K

6 0
3 years ago
three condensers are connected in series across a 150 volt supply. The voltages across them are 40,50 and 60 volts respectively,
ioda

Explanation:

Given that,

The voltages across them are 40,50 and 60 volts respectively, and the charge on each condenser is 6×10⁻⁸ C.

(a) Capacitance of capacitor 1,

C_1=\dfrac{Q}{V_1}\\\\C_1=\dfrac{6\times 10^{-8}}{40}\\\\C_1=1.5\times 10^{-9}\ F\\\\C_1=1.5\ nF

Capacitance of capacitor 2,

C_2=\dfrac{Q}{V_2}\\\\C_2=\dfrac{6\times 10^{-8}}{50}\\\\C_2=1.2\times 10^{-9}\ F\\\\C_2=1.2\ nF

Capacitance of capacitor 3,

C_3=\dfrac{Q}{V_3}\\\\C_3=\dfrac{6\times 10^{-8}}{60}\\\\C_3=1\times 10^{-9}\ F\\\\C_3=1\ nF

(b) The equivalent capacitance in series combination is :

\dfrac{1}{C}=\dfrac{1}{C_1}+\dfrac{1}{C_2}+\dfrac{1}{C_3}\\\\\dfrac{1}{C}=\dfrac{1}{1.5}+\dfrac{1}{1.2}+\dfrac{1}{1}\\\\C=0.4\ nF

Hence, this is the required solution.

5 0
3 years ago
Ryan applied a force of 10N and moved a book 30 cm in the direction of the force. How much was the workdone by Ryan?​
Xelga [282]
<h2><u>Question</u><u>:</u><u>-</u></h2>

Ryan applied a force of 10N and moved a book 30 cm in the direction of the force. How much was the work done by Ryan?

<h2><u>Answer:</u><u>-</u></h2>

<h3>Given,</h3>

=> Force applied by Ryan = 10N

=> Distance covered by the book after applying force = 30 cm

<h3>And,</h3>

30 cm = 0.3 m (distance)

<h3>So,</h3>

=> Work done = Force × Distance

=> 10 × 0.3

=> 3 Joules

\small \boxed{work \: done \:  by \: Ryan \:  = 3 \: Joules}

4 0
3 years ago
HELP!!! Why is plasma considered the most common state of matter in the universe?
olasank [31]

Clue : There is plasma in sun

4 0
3 years ago
Read 2 more answers
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