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3 years ago

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The elastic potential energy is stored in a certain spring is 14 J when it is compressed 0.240m. the spring is now cut into thre

e equal pieces. once of the pieces is then compressed by 0.150m.
How much elastic potential energy is stored in the compressed piece?

2 answers:

ELEN [110]3 years ago

6 0

Answer:

5.47 J

Explanation:

From Hook's law,

Energy stored in a elastic material = 1/2ke²

E = 1/2ke²................. Equation 1

Where k = spring constant of the material, e = extension.

make k the subject of the equation

k = 2E/e²................... Equation 2

Given: E = 14 J, e = 0.24 m

Substitute into equation 2

k = 2(14)/0.24²

k = 28/0.0576

k = 486.11 N/m.

The elastic potential energy stored in the compressed piece is

Given: e = 0.15 m

E = 1/2(466.11)(0.15²)

E = 5.47 J

Yanka [14]3 years ago

4 0

Answer:

The elastic potential energy stored in the compressed piece is 5.47 J

Explanation:

Given;

elastic potential energy stored, E = 14 J

initial compression, x = 0.240m

The elastic potential energy stored in a spring is given as;

E = ¹/₂Kx²

where;

E is elastic potential energy

K is the spring constant

x is the compression

K = 2E / x²

K = (2*14) / (0.24²)

K = 486.11 N/m

When the spring is cut into three equal pieces, and one of pieces is then compressed by 0.150m, the energy stored in this piece is calculated as;

E = ¹/₂Kx²

E = ¹/₂(486.11)(0.15²)

E = 5.47 J

Therefore, the energy stored in one of the cut pieces compressed by 0.150m is 5.47 J

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