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2 years ago

If this combination of capacitors is attached to a 9 v battery how much energy will be stored on the plates 25 15

Physics

1 answer:

Vlad1618 [11]2 years ago

4 0

The energy stored on the plates will be 378.5 J. The combination of capacitors is in series.

<h3>What is a capacitor?</h3>

A capacitor is a device that can store electrical energy. It is a two-conductor configuration separated by an insulating medium that carries charges of equal size and opposite sign.

An electric insulator or vacuum, such as glass, paper, air, or a semiconductor termed a dielectric, can be used as the non-conductive zone.

The complete question is;

"If this combination of capacitors is attached to a 9.00 V battery; how much energy will be 25 μF 15 μF stored on the plates?"

If the two capacitors are in series the equivalent capacitance will be;

$\rm \frac {1}{C} = \frac{1}{C_1}+\frac{1}{C_2} \\\\ \rm \frac {1}{C} = \frac{1}{25}+\frac{1}{15} \\\\ C = 9.375$

Energy will be stored on the plates;

$\rm E = \frac{1}{2}CV^2 \\\\ E= \frac{1}{2} \times 9.375 \mu F \times ( 9 \ V)^2\\\\E = 378.5 \ J$

Hence the energy stored on the plates will be 378.5 J.

To learn more about the capacitor, refer to the link: brainly.com/question/14048432.

#SPJ1

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A runner completes the 300-meter dash in 38 seconds. What is the speed of the runner? Round your answer to the nearest tenth.The

Galina-37 [17]

The speed of the runner is 300 m /38 seconds. You can simplify this answer to be about 7.9 m/s

7 0

3 years ago

A horizontal force of 750 N is needed to overcome the force of static friction between a level floor and a 250-kg crate. What is

Aleksandr [31]

Answer:

The acceleration of the crate is 1.8 m/s² so the answer is a.

Explanation:

The very first thing you must do when solving this problem is to draw a free body diagram. (The body diagram is attached to this answer)

So once we got the free body diagram, we can analyze it and build our sum of forces in the x and y directions. Notice that according to the diagram, there are 4 forces to this problem, Normal (N), Weight (W), kinetic friction (fk) and the 750N force.

As one may see in the free body diagram, two of the forces are vertical forces: N and W, so we can use them to build a sum of forces:

Starting with the sum of forces in the y-direction, we get:

Σ $F_{y}$ =0

We set the sum equal to zero because there is no movement in the y-direction, so the system is in vertical equilibrium.

so the sum will be:

$N-W=0$

when solving for N we get that:

N=W

where W is found by multiplying the mass of the crate by the acceleration of gravity:

N=250kg*9.8m/s²

N=2450N

Once we found the normal force, we can use it to find the kinetic friction which is given by the following formula:

$f_{k}=N$ μ

where μ is the kinetic friction coefficient.

So we get that the kinetic friction is:

$f_{k}=2450N*0.12$

$f_{k}=294$

With this information we can go ahead and find the sum of horizontal forces:

Σ $F_{x}$ =ma

In this case the sum is equal to mass times acceleration because the crate is moving horizontally due to the action of a force, so it will have an acceleration.

so the sum of forces look like this:

750N- $f_{k}$ =ma