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Stolb23 [73]
4 years ago
14

The amount of carbon dioxide (in pounds per 15,000 cubic miles) released by a certain SUV depends on its fuel efficiency accordi

ng to the formula W = 32x2 − 2080x + 44,000 (12 ≤ x ≤ 33) where x is the fuel efficiency of an SUV in miles per gallon. According to the model, what is the fuel efficiency of the SUV with the least carbon dioxide pollution?

Chemistry
1 answer:
Shtirlitz [24]4 years ago
5 0

Answer:

30 miles per gallon.

Explanation:

See picture  

When the amount of carbon is plotted based on efficiency, the following graph is obtained (see image)

when looking at the graph, it can be seen that the point of lowest emission is presented with the maximum possible efficiency, 30 miles per gallon and this value is 10400 pounds per 15000 cubic miles.  

W=32x^{2}-2080x+44000

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Carbon? i am confused, if you're asking for the element or what is happening, i need a bit of clarification!
7 0
3 years ago
Hydrogen peroxide decomposes to form water and oxygen gas according to the following equation: 2H2O2(aq)  2H2O(l) + O2(g) If 31
olya-2409 [2.1K]

Answer:

141.89 dm^3

Explanation:

The equation of the reaction is;

2H2O2(aq) --------->2H2O(l) + O2(g)

Now , we are told that the mass of hydrogen peroxide decomposed was 315g. Number of moles of hydrogen peroxide in 315g of the substance is given by;

Number of moles= mass/molar mass

Molar mass of hydrogen peroxide= 34.0147 g/mol

Number of moles= 315g/34.0147 g/mol = 9.26 moles of hydrogen hydrogen peroxide.

From the reaction equation;

2 moles of hydrogen peroxide yields 1 mole of oxygen

9.26 moles of hydrogen peroxide yields 9.26 ×1/2 = 4.63 moles of oxygen

From the ideal gas equation;

Volume of the gas V= the unknown

Pressure of the gas P= 0.792 atm

Temperature of the gas= 23°C +273 = 296 K

Number of moles of oxygen = 4.63 moles of oxygen

R= 0.082atmdm^3K-1mol-1

Hence, from PV=nRT

V= nRT/P

V= 4.63 × 0.082 × 296/0.792 = 141.89 dm^3

8 0
4 years ago
Calcular la normalidad de 1 Kg de sulfuro de aluminio en 5000 ml de solucion.
Troyanec [42]

Calculate the normality of 1 Kg of aluminum sulfide in 5000 ml of solution.

Normality comes out to be 8.11

<h3> Given </h3>
  • Mass of solute: 1000g
  • Volume of solution (V): 5000 ml = 5 liters
  • Equivalent mass of solute (E) = molar mass / n-factor

n-factor for Al_{2}S_{3} is 6 and molar mass is 148g

So, on calculating equivalent mass is equal to 24.66g

FORMULAE of Normality (N) = (Mass of the solute) / (Equivalent mass of the solute (E) × Volume of the solution (V)

                                           N=\frac{1000}{24.66*5}

                                          <u> N=8.11</u>

Therefore, normality of 1 kg aluminum sulfide is 8.11

Learn more about normality here brainly.com/question/25507216

#SPJ10

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