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3 years ago

What is a solution?

1 answer:

7 0

The correct answer is a solute and a solvent

A solution is any homogenous mixture of two or more substances. It does not necessarily have to be liquid or gaseous.

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What is the molarity of a solution containing 60. grams of NaOH dissolved in 400. mL of water?

Hunter-Best [27]

Answer: 3.75 M

Explanation:

400 mL = 0.4 L

NaOH has a molar mass of around 40 g/mol.

$\frac{60 grams}{40 g/mol}$ = 1.5 moles

Molarity = $\frac{1.5 moles}{0.4 Liters}$ = 3.75 M

8 0

2 years ago

Given 6.98 x 10 4 power grams of iron, calculate the moles of iron present

KiRa [710]

Answer:

1249.88 mol.

Explanation:

∵ no. of moles of Fe = mass of Fe/atomic weight of Fe.

<em>∴ no. of moles of Fe </em>= (6.98 x 10⁴ g)/(55.845 g/mol) = <em>1249.88 mol.</em>

6 0

2 years ago

Determine the empirical formula for a compound that is found to contain

Sphinxa [80]

Answer:

The empirical formula is PCl3

Explanation:

Mass of P is 30.97 g, thus 1.523 g of P equivalent to 0.05 moles of P

Mass of Cl is 35.45 g, thus 5.228 g of Cl equivalent to 0.15 moles of Cl

Therefore moles of P : moles of Cl = 0.05:0.15 = 1:3

Therefore the empirical formula, PCl3

7 0

3 years ago

A calorimeter contains 22.0 mL of water at 14.0 ∘C . When 2.50 g of X (a substance with a molar mass of 82.0 g/mol ) is added, i

Alik [6]

Answer:

The enthalpy change in the the reaction is -47.014 kJ/mol.

Explanation:

$X(s)+H_2O(l)\rightarrow X(aq)$

Volume of water in calorimeter = 22.0 mL

Density of water = 1.00 g/mL

Mass of the water in calorimeter = m

$m=1.00 g/mL\times 22.0 mL=22 g$

Mass of substance X = 2.50 g

Mass of the solution = M = 2.50 g + 22 g = 24.50 g

Heat released during the reaction be Q

Change in temperature =ΔT = 28.0°C - 14.0°C = 14.0°C

Specific heat of the solution is equal to that of water :

c = 4.18J/(g°C)

$Q=Mc\times \Delta T$

$Q=24.50 g\times 4.18 J/g ^oC\times 14.0^oC=1,433.74 J=1.433 kJ$

Heat released during the reaction is equal to the heat absorbed by the water or solution.

Heat released during the reaction =-1.433 kJ

Moles of substance X= $\frac{2.50 g}{82.0 g/mol}=0.03048 mol$

The enthalpy change, ΔH, for this reaction per mole of X:

$\Delta H=\frac{-1.433 kJ}{0.03048 mol}=-47.014 kJ/mol$

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2 years ago

If 35.4 liters of hydrogen gas are used, how many liters of nitrogen gas will be needed for the above reaction at STP?

CaHeK987 [17]

Answer:

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5 0

2 years ago