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Svet_ta [14]
3 years ago
5

A voltaic cell is constructed in which the anode is a Zn|Zn2+ half cell and the cathode is a Fe2+|Fe3+ half cell. The half-cell

compartments are connected by a salt bridge.(Use the lowest possible coefficients. Use the pull-down boxes to specify states such as (aq) or (s). If a box is not needed, leave it blank.)The anode reaction is: ____+_____ yeilds _____ +______The cathode reaction is: _____+_______ yeilds_____ +________The net cell reaction is: _____+ _______yeilds _______+______In the external circuit, electrons migrate _______the Fe2+|Fe3+ electrode _______the Zn|Zn2+ electrode.In the salt bridge, anions migrate ________ the Fe2+|Fe3+ compartment ________ the Zn|Zn2+ compartment.
Chemistry
1 answer:
zmey [24]3 years ago
7 0

Answer:

See below explanation

Explanation:

Checking the reduction potencials:

Zn⁺²/Zn° , E° = -0.76 V

Fe⁺²/Fe° , E° = -0.44 V

For which Fe⁺² will be the ion that will reduce, and Zn° will lose electrons

ANODE:    Zn° ⇄ Zn⁺² + 2e⁻

CATODE: Fe⁺² + 2e⁻ ⇄ Fe°

NET CELL REACTION: FeSO₄ (ac) + Zn° ⇄ Fe° + ZnSO₄ (ac)

In the external circuit, electrons will migrate from anode (Zn|Zn⁺²) to catode (Fe|Fe⁺²), and in the salt bridge; anions migrate from Fe⁺²|Fe compartment to Zn|Zn⁺² compartment

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Given the problem below, what would the first step be in solving it?
Hoochie [10]

Answer:

First step would be convert to moles

Final Answer: 37.8 g of NaCl

Explanation:

The reaction is:

2Na + Cl₂ → 2NaCI

We convert the mass of each reactant to moles:

18 g . 1mol /23g = 0.783 moles of Na

23g . 1mol / 70.9g = 0.324 moles of chlorine

We use the mole ratio to determine the limiting reactant:

Ratio is 2:1. 2 moles of Na react to 1 mol of chlorine

Then, 0.783 moles of Na, may react to (0.783 . 1)/2 = 0.391 moles.

Excellent!. We need 0.391 moles of Cl₂ and we only have 0.324 moles available. That's why the Cl₂ is our limiting reactant.

We use the mole ratio again, with the product side. (1:2)

1 mol of Cl₂ can produce 2 moles of NaCl

Then, our 0.324 moles of gas, may produce (0.324 . 2)/1 = 0.648 moles

Finally, we convert the moles to grams:

0.648 mol . 58.45g/mol =

4 0
3 years ago
An aqueous HCL solution has a proton concentration equal to 6.00 mol/L. The HCL concentration in this solution is ————M.
Harman [31]

Answer:

HCl conc.= 6.0mol/L

Explanation:

From the dissociation of HCl= 1 mole H+ and 1mol Cl-, which is equivalent stoichiometrically in concentration to that of 1 mol HCl,

4 0
3 years ago
A student conducts an experiment to determine how the temperature of water affects the time for sugar to dissolve. In each trial
Blababa [14]

What is wrong with the experimental design is that the student changed more than one independent variable.

WHAT AN EXPERIMENT SHOULD CONTAIN?

  • An experiment is a procedural method of solving a scientific problem or answering a scientific question. An ideal experiment should contain two variables namely: independent variable and dependent variable.

  • Dependent variable: This is the variable that the experimenter measures in the experiment. The dependent variable responds to changes made to the independent variable.

  • Independent variable: This is the variable that is manipulated in an experiment in order to bring about a response.

In the experiment conducted by the student in this question in order to determine how the temperature of water affects the time for sugar to dissolve. The independent variable is the DIFFERENT TEMPERATURE OF WATER while the dependent variable is the TIME TAKEN FOR SUGAR TO DISSOLVE.

N.B: An experiment should have only one independent variable and all other variables should be kept constant. This is to have a reliable result.

  • However, this student used two independent variables (temperature and amount of water) for the experiment, which is wrong for the experimental design.

Therefore, the fact that the student changed more than one independent variable is wrong for the experimental design.

Learn more: brainly.com/question/967776

4 0
3 years ago
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kakasveta [241]
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5 0
3 years ago
What mass of oxygen is needed to burn 54.0 grams of butane c4h10
Jobisdone [24]

The moles of oxygen required to burn Butane is 6 moles.

<h3>What is a Combustion Reaction?</h3>

A reaction in which fuel gets oxidised by an oxidising agent producing a large amount of heat is called a combustion reaction.

In this question

Butane is burnt with oxygen

Molar mass of C₄H₁₀ = (12.0×4 + 1.0×10) g/mol = 58.0 g/mol

Molar mass of O₂ = 16.0×2 g/mol = 32.0 g/mol

Balanced equation for the reaction:

2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O

Mole ratio C₄H₁₀ : O₂ = 2 : 13

The given mass = 54grams

moles = 54/58 = 0.93 moles

The mole of oxygen required =

0.93/ x = 2/13

0.93*13/2 = x

x = 6.045 moles

Therefore 6 moles of oxygen are required to burn Butane.

To know more about Combustion Reaction

brainly.com/question/12172040

#SPJ1

6 0
2 years ago
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