Answer:
1) The temperature inside a diesel engine is high enough for two atmospheric gases nitrogen and oxygen to react and combine to form nitrogen oxides, NOₓ
At very high temperatures of above 1,300 °C, which are temperatures obtainable in the internal combusting chamber of a diesel engine under 100% load, air containing N₂ and O₂ is sucked in, and they combine to produce approximately 85% of the NOₓ pollutants produced from moving engine sources
2) a) N₂O contributes to the Greenhouse effect and therefore global warming
b) NO₂ contributes to the formation of smog and NO₂ combines with water to produce nitric acid which falls as acid rain, and causes irritation in the eyes and the respiratory system airways
c) Nitric oxide gas, NO, has the effect of depleting the Ozone layer which increases global warming and increased penetration of UVB
Explanation:
Answer:
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Explanation:
Answer: Time required to deposit an even layer of gold with given thickness is 
sec.
Explanation:
The given data is as follows.
Surface area = 49.8 
,
Density of gold = 19.3 
,
Current = 3.15 A, thickness of gold layer = 
It is known that relation between volume, area and thickness is as follows.
V = Surface area × Thickness
= 
= 0.05988 
Therefore, we will calculate the time required to deposit an even layer of gold with given thickness is calculated as follows.
= sec
Thus, we can conclude that time required to deposit an even layer of gold with given thickness is sec.
Answer is: 162 g of beryllium.
Chemical reaction: Be + 2H₂O → Be(OH)₂ + H₂.
m(H₂) = 36,0 g.
m(Be) = ?
n(H₂) = m(H₂) ÷ M(H₂)
n(H₂) = 36,0 g ÷ 2 g/mol = 18 mol.
from reaction: n(Be) : n(H₂) = 1 : 1.
n(Be) = n(H₂) = 18 mol.
m(Be) = n(Be) · M(Be).
n(Be) = 18 mol · 9 g/mol = 162 g.
Answer:
290.32 g
Explanation:
First we <u>calculate the volume</u> of the cube:
- Volume = (3.20 cm)³ = 32.768 cm³
Now we <u>convert cubic centimeters to mililiters</u>:
- 32.768 cm³ * 1 mL / 1 cm³ = 32.768 mL
Finally we <u>calculate the mass</u>, using the <em>equation for density</em>:
- mass = 8.86 g/mL * 32.768 mL = 290.32 g
