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Kamila [148]
3 years ago
10

Solve by a 1 variable equation -3(x-3)=x+9-4x

Chemistry
1 answer:
Otrada [13]3 years ago
5 0
-3(x - 3) = x + 9 - 4x

Firstly, before we simplify the whole thing altogether, let's simplify each respective side. Distribute accordingly on the left side (the number outside the parentheses is distributed to the numbers inside the parentheses), and we can add the numbers with variables together on the right side.

-3x + 9 = -3x + 9

Now, let's add 3x to both sides, to simplify both sides now. This leaves us with: 1, I believe, since -3 ÷ -3 is 1.

x = x, and since x also equals to 1, our answer is 1. And once you check, substituting 1 for x, you will find that 1 is the correct answer.
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The given question is incomplete. The complete question is as follows.

A certain liquid has a normal boiling point of 124.2^{o}C and a boiling point elevation constant k_{b} = 0.62 ^{o}C kg mol^{-1}. A solution is prepared by dissolving some sodium chloride (NaCl) in 6.50 g of X. This solution boils at 127.4^{o}C. Calculate the mass of NaCl that was dissolved. Round your answer to significant digits.

Explanation:

As per the colligative property, the elevation in boiling point will be as follows.

     

T = boiling point of the solution =

T_{o} = boiling point of the pure solvent = 124.2^{o}C

K_{b} = elevation of boiling constant = 0.62 ^{o}C kg mol^{-1}

We will calculate the molality as follows.

     molality = \frac{\text{maas of solute}}{\text{molar mass of solute}} \times \frac{1000}{\text{mass of solvent in g}}

i = vant hoff's factor

As NaCl is soluble in water and dissociates into sodium and chlorine ions so i = 2.

Putting the given values into the above formula as follows.  

    T - T_{o} = i \times K_{b} \times \text{molality of solution}

  (127.4 - 124.2)^{o}C = 2 \times 0.62 \times \frac{m}{60} \times \frac{1000}{650}

                  m = 100 g

Therefore, we can conclude that 100 g of NaCl was dissolved.

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