All categories

3 years ago

Solve by a 1 variable equation -3(x-3)=x+9-4x

1 answer:

5 0

-3(x - 3) = x + 9 - 4x

Firstly, before we simplify the whole thing altogether, let's simplify each respective side. Distribute accordingly on the left side (the number outside the parentheses is distributed to the numbers inside the parentheses), and we can add the numbers with variables together on the right side.

-3x + 9 = -3x + 9

Now, let's add 3x to both sides, to simplify both sides now. This leaves us with: 1, I believe, since -3 ÷ -3 is 1.

x = x, and since x also equals to 1, our answer is 1. And once you check, substituting 1 for x, you will find that 1 is the correct answer.

You might be interested in

Lpg contains ? (<br> a. methane (<br> b. butane (<br> c. eyhane (<br> d. none of them

disa [49]

Lpg contains ethane,propane,and butane..hope it helps

4 0

4 years ago

Find the standard enthalpy of formation of ethylene, C2H4(g), given the following data: C2H4(g) + 3 O2(g) --> 2CO2(g) + 2 H2O

Brums [2.3K]

Answer : The standard enthalpy of formation of ethylene is, 52.4 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The formation reaction of $C_2H_4$ will be,

$2C(s)+2H_2(g)\rightarrow C_2H_4(g)$ $\Delta H_{formation}=?$

The intermediate balanced chemical reaction will be,

(1) $C_2H_4(g)+3O_2(g)\rightarrow 2CO_2(g)+2H_2O(l)$ $\Delta H_1=-1411kJ$

(2) $C(s)+O_2(g)\rightarrow CO_2(g)$ $\Delta H_2=-393.5kJ$

(3) $H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l)$ $\Delta H_3=-285.8kJ$

Now we will reverse the reaction 1, multiply reaction 2 and 3 by 2 then adding all the equation, we get :

(1) $2CO_2(g)+2H_2O(l)\rightarrow C_2H_4(g)+3O_2(g)$ $\Delta H_1=+1411kJ$

(2) $2C(s)+2O_2(g)\rightarrow 2CO_2(g)$ $\Delta H_2=2\times (-393.5kJ)=-787kJ$

(3) $2H_2(g)+2O_2(g)\rightarrow 2H_2O(l)$ $\Delta H_3=2\times (-285.8kJ)=-571.6kJ$

The expression for enthalpy of formation of $C_2H_4$ will be,

$\Delta H_{formation}=\Delta H_1+\Delta H_2+\Delta H_3$

$\Delta H=(+1411kJ)+(-787kJ)+(-571.6kJ)$

$\Delta H=52.4kJ$

Therefore, the standard enthalpy of formation of ethylene is, 52.4 kJ

7 0

3 years ago

Which is TRUE of the reactants in this displacement reaction? Fe + 2HCI --> FeCI2 + H2

Masteriza [31]

I would go with C, because you would always start with products and end with reactants.

7 0

3 years ago

Read 2 more answers

Which kind of covalent bond has unequal sharing of electrons

lutik1710 [3]

Polar.

Polar bonds have unequal sharing electrons while nonpolar, the opposite, has equal sharing electrons. This is a tactic typically used to determine whether or not a compound or element itself is polar or nonpolar.

Hope this helps!

7 0

3 years ago

Read 2 more answers

Characteristics of a substance that can be measured or observed by changing the identity of the material is a

algol [13]

C cause ur changing the identity of the material

4 0

3 years ago