Hi,
your answer would be false. But it seems you already knew that.
I hoped I helped and if you need help you could always ask me :)
-Dawn
Answer:
Lead sulfite is the inorganic compound with the formula PbSo3 or O3PbS.
Explanation:
Answer:
0.0184
Explanation:
Let's consider the following reaction at equilibrium.
2 HI(g) ⇌ H₂(g) + I₂(g)
The concentration equilibrium constant (Kc) is equal to the product of the concentration of the products raised to their stoichiometric coefficients divided by the product of the concentration of the reactants raised to their stoichiometric coefficients.
Kc = [H₂] × [I₂] / [HI]²
Kc = (4.78 × 10⁻⁴) × (4.78 × 10⁻⁴) / (3.52 × 10⁻³)²
Kc = 0.0184
Argon monatomic in nature because it is a noble gas and has completely filled shells and thus does not form a bond with other elements.
Answer:
Ka = 6.02x10⁻⁶
Explanation:
The equilibrium that takes place is:
We <u>calculate [H⁺] from the pH</u>:
- [H⁺] =
Keep in mind that [H⁺]=[A⁻].
As for [HA], we know the acid is 0.66% dissociated, in other words:
We <u>calculate [HA]</u>:
Finally we <u>calculate the Ka</u>:
- Ka =
![\frac{[9.12x10^{-4}]*[9.12x10^{-4}]}{[0.138]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5B9.12x10%5E%7B-4%7D%5D%2A%5B9.12x10%5E%7B-4%7D%5D%7D%7B%5B0.138%5D%7D)
= 6.02x10⁻⁶
