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3 years ago

Within a molecule of nitrous oxide, N2O, an atom of nitrogen combines with an atom of oxygen in a(n)

Chemistry

1 answer:

Marianna [84]3 years ago

4 0

Can be more specific?

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If the gravitational force exists between all objects in the universe, why aren’t people affected by the gravitational force exe

AveGali [126]

Answer:

has a very small range

Explanation:

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2 years ago

It has been suggested that the surface melting of ice plays a role in enabling speed skaters to achieve peak performance. Carry

vesna_86 [32]

Explanation:

Relation between pressure, latent heat of fusion, and change in volume is as follows.

$\frac{dP}{dT} = \frac{L}{T \times \Delta V}$

Also, $\frac{L}{T} = \Delta S^{fusion}_{m}$

where, $\Delta V^{fusion}_{m}$ is the difference in specific volumes.

Hence, $\frac{dP}{dT} = \frac{\Delta S^{fusion}_{m}}{\Delta V^{fusion}_{m}}$

As, $\Delta S^{fusion}_{m} = \frac{L}{T} = \frac{6010}{273.15}$ = 22.0 J/mol K

And, $\Delta V^{fusion}_{m} = \frac{M}{d_{H_{2}O}} - \frac{M}{d_{ice}}$ ...... (1)

where, $d_{H_{2}O}$ = density of water

$d_{ice}$ = density of ice

M = molar mass of water = $18.02 \times 10^{-3} kg$

Therefore, using formula in equation (1) we will calculate the volume of fusion as follows.

$\Delta V^{fusion}_{m} = \frac{M}{d_{H_{2}O}} - \frac{M}{d_{ice}}$

= $\frac{18.02 \times 10^{-3}}{997} - \frac{18.02 \times 10^{-3}}{920}$

= $-1.51 \times 10^{-6}$

Therefore, calculate the required pressure as follows.

$\frac{dP}{dT} = \frac{22}{-1.51 \times 10^{-6}}$

= $1.45 \times 10^{7} Pa/K$

or, = 145 bar/K

Hence, for change of 1 degree pressure the decrease is 145 bar and for 4.7 degree change dP = $145 \times 4.7 bar$

= 681.5 bar

Thus, we can conclude that pressure should be increased by 681.5 bar to cause 4.7 degree change in melting point.

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3 years ago

Lanthanium found in the......... period

Gnesinka [82]

I'm preatty sure it is in the periodic table xxx

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3 years ago

Find the mass that corresponds to each number of

jeka94

Answer:159.7 g.

Explanation:

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3 years ago

Read 2 more answers

Calculate how many grams of of copper sulfate pentahydrate are required to prepare

Rzqust [24]

Molar mass CuSO4.5H2O => 249.685 g/mol

Volume in liters => 100 mL / 1000 => 0.1 L

1 L ----------------- 0.05 M
0.1 L -------------- ?? ( moles of copper sulfate pentahydrate )

0.1 x 0.05 / 1 => 0.005 moles

1 mole ------------- 249.685 g
0.005 moles ------- ( mass of copper sulfate pentahydrate )

0.005 x 249.685 / 1 => 1.28425 g CuSO4.5H2O

hope this helps!

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3 years ago