The critical angle for the interface between water and diamond is 33.4 degrees.
<h3>What is the critical angle?</h3>
The greatest angle at which a ray of light traveling through one transparent medium can hit the border between that medium and a second of lower refractive index.
It strikes the border without being completely reflected within the first medium is called the critical angle in optics.
Thus, the critical angle for the interface between water and diamond is 33.4 degrees.
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Answer:
See explaination
Explanation:
See attachment for the structure of the acetal that you would obtain by reaction of cyclopentanone with 1-propanol.
Answer:
0.42%
Explanation:
<em>∵ pH = - log[H⁺].</em>
2.72 = - log[H⁺]
∴ [H⁺] = 1.905 x 10⁻³.
<em>∵ [H⁺] = √Ka.C</em>
∴ [H⁺]² = Ka.C
∴ ka = [H⁺]²/C = (1.905 x 10⁻³)²/(0.45) = 8.068 x 10⁻⁶.
<em>∵ Ka = α²C.</em>
Where, α is the degree of dissociation.
<em>∴ α = √(Ka/C) </em>= √(8.065 x 10⁻⁶/0.45) = <em>4.234 x 10⁻³.</em>
<em>∴ percentage ionization of the acid = α x 100</em> = (4.233 x 10⁻³)(100) = <em>0.4233% ≅ 0.42%.</em>
Primary producers i believe
