Methane and water because they are both compounds
Answer:
9
Explanation:
Given parameters:
Concentration of OH⁻ [OH]= 1 x 10⁻⁹M
Solution:
To find the pOH of a solution can be found using the expression below:
pOH = -log₁₀[OH]
[OH] = concentration of the hydroxyl ions
pOH = -log₁₀(1 x 10⁻⁹) = - x -9 = 9
Answer:
8moles
Explanation:
We are given the mass of ammonia to be 136g
Ammonia = NH₃
Let us find the number of moles in ammonia;
Number of moles = 
Molar mass of ammonia = 14 + 3(1) = 17g/mol
so;
Number of moles = 
= 8moles
Answer:
30.8 g of water are produced
Explanation:
First of all we need the equation for the production of water:
2H₂ + O₂ → 2H₂O
2 moles of hydrogen react with 1 mol of oxygen in order to produce 2 moles of water.
As we assume, the oxygen in excess, we determine the moles of H₂.
1.03ₓ10²⁴ molecules . 1 mol/ 6.02ₓ10²³ molecules = 1.71 moles
Ratio is 2:2, so 1.71 moles will produce 1.71 moles of water
Let's convert the moles to mass: 1.71 mol . 18g / 1mol = 30.8 g of water are produced
