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NARA [144]
3 years ago
11

What mass of chromium would be produced from the reaction of 57.0 g of potassium with 199 g of chromium(II) bromide according to

the following reaction? 2 K + CrBr2 2 KBr + Cr
Chemistry
1 answer:
fredd [130]3 years ago
6 0

Answer:

Mass of Chromium produced = 37.91 grams

Explanation:

2K + CrBr₂  →  2KBr + Cr

2mole     1 mole                1 mole

mass of Potassium = 57.0 grams

molar mass of Potassium = 39.1 g/mol

no of moles of Potassium = 57.0 / 39.1 = 1.458 moles

mass of CrBr₂= 199 grams

molar mass of CrBr₂ = 211.8 gram/mole

no of moles of CrBr₂ = 199 / 211.8 = 0.939 mole

From chemical equation

1 mole of CrBr₂ = 2 moles of K

∴ 0.939 moles of CrBr₂ = ?

   ⇒ 0.939 x 2/1 = 1.878 moles of K

1.878 moles of K is needed, but there is 1.458 moles of K. So, Potassium is completed first during the reaction . Hence, Potassium is limiting reagent. and CrBr₂ is excess reagent .

From chemical equation

2 moles of K = 1 mole of Cr

∴ 1.458 moles of K = ?

   ⇒ 1.458 x 1/ 2 = 0.729 moles of Cr

no of moles of Cr formed = 0.729 moles

molar mass of Cr = 52.0 g/mol

mass of one mole of Cr = 52.0 grams

mass of 0.729 moles of Cr = 52.0 x 0.729 = 37.908 grams

mass of Chromium produced = 37.91 grams

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Explanation:

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Out of the given compounds only C₂H₂Cl₂ has double bond so this compound contains carbon with sp² hybridization .

Rest have sp³ hybridization because they are saturated compounds .

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a serving of a particular fruit dessert contains 20.0 g of sugar. if all the sugar is sucrose, c12h22o11, how many molecules of
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Taking into account the definition of Avogadro's number and molar mass, 3.49334×10²² molecules of sucrose are present.

<h3>Definition of molar mass</h3>

The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

<h3>Avogadro's Number</h3>

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

<h3>Molecules of sugar in this case</h3>

In first place, the molar mass of sucrose is 342 g/mole. So, you can apply the following rule of three: If by definition of molar mass 342 grams of the compound are contained in 1 mole, 20 grams of the compound are contained in how many moles?

amount of moles=\frac{20 gramsx1 mole}{342 grams}

<u><em>amount of moles= 0.058 moles</em></u>

Now, considering the Avogadro's number, you can apply the following rule of three: If 1 mole of the compound contains 6.023×10²³ molecules, 0.058 moles contains how many molecules?

amount of moleculas= (6.023×10²³ molecules × 0.058 moles)÷ 1 mole

<u><em>amount of molecules= 3.49334×10²² molecules</em></u>

Finally, 3.49334×10²² molecules of sucrose are present.

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Avogadro's Number:

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#SPJ12

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