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Free_Kalibri [48]
3 years ago
12

Kevin is working on a model that shows the positions of Earth, the Moon, and the Sun during the phases of

Chemistry
2 answers:
mr_godi [17]3 years ago
6 0

Answer: A. With Earth between the Moon and the Sun.

Explanation:

sergij07 [2.7K]3 years ago
5 0

Answer:

Explanation:what’s the answer

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What are the molality and mole fraction of solute in a 22.3 percent by mass aqueous solution of formic acid (HCOOH)?
Vanyuwa [196]

Answer:

Mole fraction for solute = 0.1, or 10%

Molality = 6.24 mol/kg

Explanation:

22.3% by mass → In 100 g of solution, we have  22.3 g of HCOOH

Mass of solution = 100 g

Mass of solute = 22.3 g

Mass of solvent = 100 g - 22.3g = 77.7 g

Let's convert the mass to moles

22.3 g . 1mol/ 46 g = 0.485 moles

77.7 g. 1mol / 18 g = 4.32 moles

Total moles = 4.32 moles + 0.485 moles = 4.805 moles

Xm for solute = 0.485 / 4.805 = 0.100 → 10%

Molality → mol/ kg → we convert the mass of solvent to kg

77.7 g.  1 kg / 1000g = 0.0777 kg

0.485 mol / 0.0777 kg = 6.24 m

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3 years ago
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Easy questions ha chemistry
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3 years ago
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Whenever you see an ‘N’, ‘S’, or ‘P’ followed by a bunch of oxygens you know you have a
Leya [2.2K]
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Is there are a total of 7.3 x 10^29 atoms in a sample of glucose, C6H12O6(s),what amount in miles of glucose is in the sample?
Vadim26 [7]

(7.3 x 10^29 atoms) / (24 atoms/molecule) / (6.022 x 10^23 molecules/mol) =  

5.1 x 10^4 mol C6H12O6

4 0
3 years ago
To what volume in millimeters must 50.0 mL of 18.0 M H2SO4 be diluted to obtain 4.35 M H2SO4?
poizon [28]
We know that to relate solutions of with the factors of molarity and volume, we can use the equation: M_{1}  V_{1} = M_{2}  V_{2}

**NOTE: The volume as indicated in this question is defined in L, not mL, so that conversion must be made. However it is 1000 mL = 1 L.

So now we can assign values to these variables. Let us say that the 18 M H_{2}  SO_{4} is the left side of the equation. Then we have:

(18 M)(0.050 L)=(4.35M) V_{2}

We can then solve for V_{2}:

V_{2}= \frac{(18M)(0.05L)}{4.35M} and V_{2} =0.21 L or 210 mL

We now know that the total amount of volume of the 4.35 M solution will be 210 mL. This is assuming that the entirety of the 50 mL of 18 M is used and the rest (160 mL) of water is then added.


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3 years ago
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