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kicyunya [14]
4 years ago
11

If in a single slit diffraction experiment the wavelength is increased, which of the following happens to the diffraction patter

n?A) The central maximum broadens.
B) The minima get closer together.
C) The central maximum narrows.
D) The minima remain the same.
E) Eventually you get double slit interference
Physics
1 answer:
Nutka1998 [239]4 years ago
7 0

Answer:

The central maximum broadens.

Explanation:

In the diffraction pattern in a single slit diffraction experiment. The position of maxima is given by :

y=\dfrac{m\lambda D}{d}

Where

m is the order

D is the distance between slit and the screen

d is the slit width

It is clear that on increasing the wavelength in a single slit, the central maximum broadens. Hence, the correct option is (A).

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Look at the diagram showing resistance and flow of electrons.
poizon [28]

The answer would be:

D.

X: Low potential energy

Y: High Potential energy

Z: Flow of electrons

Z is clearly the flow of electrons, as shown by the arrow demonstrating the direction of the flow. So you can easily cross out choices B and C. Now, you can see that Y has more energy stored and X has a lot less, so you can conclude that Y has high potential energy while X has low potential energy.


8 0
3 years ago
Read 2 more answers
Which of the following is characteristics of both sound and light waves
saw5 [17]

==> they carry energy from one place to another;

==> their speed depends on properties of the medium;

==> they undergo reflection, refraction, diffraction, and dispersion;

==> their intensity varies as the inverse square of the distance they travel;

3 0
3 years ago
Amanda then used an inclined plane to push the same crate into the truck. She exerts a force of 77.5N a distance of 3.1m. What i
Kazeer [188]

Answer: 240.25joules

Explanation:

Work is done when force is applied on an object over a distance. It is measured in joules.

Thus, Workdone = Force x distance

Since, Work = ? (unknown value)

Force = 77.5N

Distance = 3.1metres

Workdone = 77.5 N x 3.1metres

= 240.25 joules

Thus, Amanda did a work of 240.25joules on the crate

8 0
3 years ago
Two resistors, one with 7.00 Ω of resistance and the other with 11.00 Ω of resistance, are connected in series to a 9.00 V batte
IRINA_888 [86]

Answer:

4.5 W

Explanation:

Applying,

P = V²/(R₁+R₂).................. Equation 1

Where P = Power, V = Voltage, R₁ and R₂ = values of the two resistor.

From the question,

Given: V = 9.00 V, R₁ = 7.00 Ω, R₂ = 11.00  Ω

Substitute these values into equation 1

P = 9²/(7+11)

P = 81/(18)

P = 4.5 Watt.

Hence the power dessipated by the two resistors is 4.5 watt

5 0
3 years ago
A 4.5-kg object oscillates on a horizontal spring with an amplitude of 3.8 cm. Its maximum acceleration is 26 m/s2 . Find (a) th
zimovet [89]

Answer:

F = - K X     force constant for spring

a = F / m      maximum acceleration

F = 4.5 kg * 26 m/s^2 = 117 Newtons

(A)  K = 117 N / .038 m = 3079 N/m

ω = (K/M)^1/2 = (117/5)^1/2 = 4.84 / sec

(B) f = ω / 2 pi = 4.84 / 6.28 = .77 /sec

(C) P = 1 / f = 1/.77   = 1.30 sec

3 0
3 years ago
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