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2 years ago

What is the formula for calculating the efficiency of a heat engine?

Physics

1 answer:

Olegator [25]2 years ago

7 0

Explanation:

The efficiency of a heat engine is defined as the ratio of the work output to the heat input into the system.

It is highly impossible to get an engine that is 100% efficient.
A heat engine that is 100% efficient suggests that all the heat input into the system is used to do work completely.
There is no heat loss.

Efficiency = $\frac{work output}{heat input}$ x 100

Efficiency has no unit

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A ball rolls forward in the grass slowing down as it rolls?

olga nikolaevna [1]

Yes it does, uh huh. It slows down as it rolls. That's a fact.

In order for the ball to roll forward, it has to push grass out of the way. That takes energy. To bend each blade of grass out of its way, the ball has to use a tiny bit of the kinetic energy that it has, so it gradually runs out of kinetic energy. When its kinetic energy is all gone, it stops moving.

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3 years ago

Which of the following actions will increase the current induced in a wire by a<br> magnetic field?

In-s [12.5K]

Answer:

The induced current can be increased in the coil in the following ways: By increasing the strength of the magnet. By increasing the speed of the magnet through the coil.

Explanation:

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2 years ago

Draw vectors to represent these motions:<br>moving 3 cm to the right<br>moving 2 cm to the left

Ira Lisetskai [31]

Vector. Oh yeeeeeeeeahhh

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1 year ago

Consider the nearly circular orbit of Earth around the Sun as seen by a distant observer standing in the plane of the orbit. Wha

ikadub [295]

We have that the spring constant is mathematically given as

$k=2.37*10^{11}N/m$

Generally, the equation for angular velocity is mathematically given by

$\omega=\sqrt{k}{m}$

Where

k=spring constant

And

$\omega =\frac{2\pi}{T}$

Therefore

$\frac{2\pi}{T}=\sqrt{k}{n}$

Hence giving spring constant k

$k=m((\frac{2 \pi}{T})^2$

Generally

Mass of earth $m=5.97*10^{24}$

Period for on complete resolution of Earth around the Sun

$T=365 days$

$T=365*24*3600$

Therefore

$k=(5.97*10^{24})((\frac{2 \pi}{365*24*3600})^2$

$k=2.37*10^{11}N/m$

In conclusion

The effective spring constant of this simple harmonic motion is

$k=2.37*10^{11}N/m$

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3 years ago

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Answer:

Explanation:

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2 years ago

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