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STatiana [176]
4 years ago
13

25% part (c) assume that d is the distance the cheetah is away from the gazelle when it reaches full speed. Derive an expression

in terms of the variables d, vcmax and vg for the time, tc, it takes the cheetah to catch the gazelle.
Physics
1 answer:
levacccp [35]4 years ago
6 0

maximum speed of cheetah is

v_1 = v_{max}

speed of gazelle is given as

v_2 = v_{g}

Now the relative speed of Cheetah with respect to Gazelle

v_{12} = v_1 - v_2

v_{12} = v_{max} - v_g

now the relative distance between Cheetah and Gazelle is given initially as "d"

now the time taken by Cheetah to catch the Gazelle is given as

d = v_{12}* t

so by rearranging the terms we can say

t = \frac{d}{v_{12}}

t = \frac{d}{v_{max} - v_g}

so above is the relation between all given variable

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A small 12.00 g plastic ball is suspended by a string in a uniform, horizontal electric field. If the ball is in equilibrium whe
notsponge [240]

Answer:

Q = \frac{0.068}{E}

where E = electric field intensity

Explanation:

As we know that plastic ball is suspended by a string which makes 30 degree angle with the vertical

So here force due to electrostatic force on the charged ball is in horizontal direction along the direction of electric field

while weight of the ball is vertically downwards

so here we have

QE = F_x

mg = F_y

since string makes 30 degree angle with the vertical so we will have

tan\theta = \frac{F_x}{F_y}

tan30 = \frac{QE}{mg}

Q = \frac{mg}{E}tan30

Q = \frac{0.012\times 9.81}{E} tan30

Q = \frac{0.068}{E}

where E = electric field intensity

5 0
3 years ago
what would the mass be of an object that was moving at a velocity of 35 m/s and has a kinetic energy of 500j be?
bearhunter [10]

Answer:

0.816 kg

Explanation:

E_k=\frac{1}{2}mv^{2}\\

so m=\frac{2E_k}{v^2}=\frac{2\times500}{35^2}=0.816 kg

5 0
2 years ago
100 POINTS!!! MAKE YOU BRAINLIEST! ASAP PLEAZE HURRY
kolezko [41]

1. I think it was the Big Bang Theory. It states that the universe was originally a small, immensely dense packet of energy that exploded causing the elements and space to form.

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It is due to gravitational force that holds planets with stars, moons with their planets and stars in galaxies. Had there been no gravitational force, the stars would not have formed and for the fact, any other body in this universe. Gravitational force causes the moons to revolve about planets, planets to revolve about star and star to revolve about the center of galaxy.

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6. Earth is slightly closer to the sun in January than in July. However, summer is warmer because the tilt of the earth exposes the hemisphere to more direct light during the summer months.

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As for the dates, the spring equinox is on March 20 or 21, the summer solstice is on June 22 or 23, the fall equinox is on September 23 or 24, and the winter solstice is on December 22 or 23.

10. Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune.

11. Mercury, Mars, Venus, Earth, Neptune, Uranus, Saturn, and Jupiter

12. Mercury, Mars, Uranus, Venus, Earth, Neptune, Saturn, and Jupiter

Earth  

Earth, the third planet from the sun and the largest terrestrial

planet, is the only planet known to host living beings and the only one known to have liquid water on its surface. T

Jupiter  

The largest and most distinctive of the storms, the Great Red Spot, is larger than Earth. Jupiter has 63 moons and a faint ring system.

Mars

Some of the surface features of Mars, such as dry river beds, hint to the possibility that water previously existed on the planet and may still flow under the surface.

Mercury  

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Neptune  

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Saturn

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Uranus  

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Venus

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4 0
3 years ago
In which position is it winter in North America? *
Dominik [7]

Answer:

position 4

Explanation:

if the north is tilted away it gets no sunlight, so its winter

6 0
3 years ago
Read 2 more answers
A 41 kg girl and a 5.0 kg sled are on the frictionless ice of a frozen lake, 15 m apart but connected by a rope of negligible ma
goldfiish [28.3K]

(a) 0.8 m/s^2

The force exerted on the sled is F = 4.0 N. We can calculate the acceleration of the sled by using Newton's second law:

F=ma

where

m = 5.0 kg is the mass of the sled

a is the acceleration of the sled

Solving the equation for a, we find:

a=\frac{F}{m}=\frac{4.0 N}{5.0 kg}=0.8 m/s^2

(b) 0.098 m/s^2

According to Newton's third law (action-reaction law), since the girl exerts a force on the sled, then the sled exerts an equal and opposite force on the girl as well. This means that the force exerted on the girl is also F = 4.0 N. As before, we can calculate the acceleration of the girl by using Newton's second law:

F=ma

where

m = 41 kg is the mass of the girl

a is the acceleration of the girl

Solving the equation for a, we find:

a=\frac{F}{m}=\frac{4.0 N}{41 kg}=0.098 m/s^2

(c) 5.8 s

Taking the initial position of the girl as x = 0, the position at time t of the girl is given by:

x(t)=\frac{1}{2}a_g t^2

where a_g = 0.098 m/s^2 is the acceleration of the girl.

The sled starts instead its motion from x = 15 m, so its position at time t is given by

x'(t)=15-\frac{1}{2}a_s t^2

where a_s=0.8 m/s^2 is the acceleration of the sled, and the negative sign is due to the fact that the sled accelerates in opposite direction to the girl's acceleration.

The girl and the sled meet when x(t) = x'(t). So, we find:

\frac{1}{2}a_g t^2=15-\frac{1}{2}a_s t^2\\(a_g+a_s) t^2=30 m\\t=\sqrt{\frac{30 m}{a_g+a_s}}=\sqrt{\frac{30 m}{0.8 m/s^2+0.098 m/s^2}}=5.8 s

4 0
4 years ago
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