Answer:
4.7 atm
Explanation:
From the question given above, the following data were obtained:
Total pressure (P) = 15.3 atm
Pressure of Helium, P(He) = 3.2 atm
Pressure of Oxygen, P(O) = 7.4 atm
Pressure of Argon, P(Ar) =?
The pressure of Argon, P(Ar) in the tank can be obtained as illustrated below:
P = P(He) + P(O) + P(Ar)
15.3 = 3.2 + 7.4 + P(Ar)
15.3 = 10.6 + P(Ar)
Collect like terms
15.3 – 10.6 = P(Ar)
4.7 = P(Ar)
P(Ar) = 4.7 atm
Therefore, the pressure of Argon, P(Ar) in the tank is 4.7 atm
Answer : The mass of chlorine reacted with the phosphorus is, 53.25 grams.
Explanation :
First we have to calculate the moles of phosphorus.
Now we have to calculate the moles of 
The balanced chemical reaction is:
From the balanced chemical reaction, we conclude that
As, 2 moles of phosphorous react with 3 moles of
So, 0.5 moles of phosphorous react with 
moles of
Now we have to calculate the mass of
Molar mass of = 71 g/mol
Therefore, the mass of chlorine reacted with the phosphorus is, 53.25 grams.
Generally, the top elements in group 16 will have a charge of -2, although the entire group isn't standardized.
Here, we apply a mass balance:
Moles of chloride ions in final solution = sum of moles of chloride ions in added solutions
We must also not that each mole of sodium chloride will release one mole of chloride ions, while each mole of magnesium chloride will release two moles of chloride ions.
Moles = concentration * volume
Moles in final solution = moles in NaCl solution + moles in MgCl₂ solution
C * (150 + 250) = 1.5 * 150 + 2 * 0.75 * 250
C = 1.5 M
The final concentration is 1.5 M
