Answer:
0.324
Explanation:
The following data were obtained from the question:
Concentration of NH3, [NH3] = 0.25 M
Concentration of H2, [H2] = 0.3 M
Concentration of N2, [N2] = 0.75 M
Equilibrium constant (Kc) =.?
The balanced equation for the reaction is given below:
2NH3 <==> 3H2 + N2
The equilibrium constant, Kc for a given reaction is the ratio of the concentration of the products raised to their coefficient to the concentration of the reactants raised to their coefficient. Thus, the equilibrium constant for the above reaction can be obtained as illustrated below:
Kc = [H2]³ [N2] / [NH3]²
Concentration of NH3, [NH3] = 0.25 M
Concentration of H2, [H2] = 0.3 M
Concentration of N2, [N2] = 0.75 M
Equilibrium constant (Kc) =.?
Kc = [H2]³ [N2] / [NH3]²
Kc = [0.3]³ × [0.75] / [0.25]²
Kc = (0.027 × 0.75) / 0.0625
Kc = 0.02025 / 0.0625
Kc = 0.324
Therefore, the equilibrium constant for the reaction is 0.324
