Answer:
50.0 °C
Explanation:
If all other variables are being held constant, you can find the temperature using Guy-Lussac's Law. The equation looks like this:
P₁ / T₁ = P₂ / T₂
In this equation, "P₁" and "T₁" represent the initial pressure and temperature. "P₂" and "T₂" represent the final pressure and temperature. You can find the missing temperature (T₂) by plugging the given values into the equation and simplifying.
P₁ = 405 pKa P₂ = 1013 pKa
T₁ = 20 °C T₂ = ? °C
P₁ / T₁ = P₂ / T₂ <----- Guy-Lussac's Law
405 pKa / 20 °C = 1013 pKa / T₂ <----- Insert values
20.25 = 1013 pKa / T₂ <----- Divide 20 from 405
20.25 x T₂ = 1013 pKa <----- Multiply both sides by T₂
T₂ = 50.0 °C <----- Divide both sides by 20.25
It would be D. A and B are physical properties
Answer:
1.The metalloids; boron (B), silicon (Si), germanium (Ge), arsenic (As), antimony (Sb), tellurium (Te), polonium (Po) and astatine (At) are the elements found along the step like line between metals and non-metals of the periodic table.
2.hydrogen
The elements generally classified as nonmetals include one element in group 1 (hydrogen);
3.element iron
The element iron is in group 8, and therefore has two or three apparent valence electrons.
Answer:
P2 = 226.6 kPa (Approx)
Explanation:
Given:
Temperature t = 25ºC
Old volume v1 = 145 ml
Old pressure p1 = 125 KPa
New volume v2 = 80 ml
Find:
New pressure p2
Computation:
p1v1 = p2v2
125 x 145 = P2 x 80
P2 = 226.6 kPa (Approx)
Answer:
You'll have to record the observations in appropriate ways and organize them The way you collect your data should relate to how you're planning to analyze and use it These might for instance include entering numerical observations into a Qualitative data are collected as descriptions anecdotes opinions quote
Explanation: