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3 years ago

How do you find the scientific period and frequency

Physics

1 answer:

Hunter-Best [27]3 years ago

5 0

Period is the inverse of freguency (1/f) and freqquency is the inverse of period (1/p)

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A force of 52N acts upon a 4kg block sitting on the ground. Calculate the acceleration of the object.

irina1246 [14]

Answer:

$a=13\ m/s^2$

Explanation:

Given that,

Force, F = 52 N

Mass of the block, m = 4 kg

We need to find the acceleration of the object. We know that,

F = ma

Put the values,

$a=\dfrac{F}{m}\\\\a=\dfrac{52}{4}\\\\a=13\ m/s^2$

So, the acceleration of the object is equal to $13\ m/s^2$ .

5 0

3 years ago

a wave is represented by the equation y=0.5 sin0.6×(x-60t) where the distance x is measured in cm and time t is seconds. what is

Grace [21]

Answer:

lamda=10.5m

Explanation:

using the equation of progressive wave.

y=Asin(wt-kx)

comparing the two equations together, we have

kx=0.6x , k=0.6

k=2π/λ

0.6=2*3.142/λ

cross multiply

0.6λ=6.284

divide both sides by 0.6

λ=6.284/0.6

λ=10.47m

approximate

λ=10.5m

5 0

3 years ago

Stars appears to move from east to west because

Liula [17]

Answer:

The earth rotates from West to east

Explanation:

Every planet in our solar system rotates around their axis in West to east direction.
Only Venus is the only planet which rotates from east to west

8 0

3 years ago

Read 2 more answers

Calculate the ratio of the drag force on a jet flying at 1190 km/h at an altitude of 7.5 km to the drag force on a prop-driven t

Bond [772]

Answer:

$\frac{D_{jet}}{D_{prop}}=2.865$

Explanation:

Given data

Speed of jet Vjet=1190 km/h

Speed of prop driven Vprop=595 km/h

Height of jet 7.5 km

Height of prop driven transport 3.8 km

Density of Air at height 10 km p7.8=0.53 kg/m³

Density of air at height 3.8 km p3.8=0.74 kg/m³

The drag force is given by:

$D=\frac{1}{2}CpAv^2\\$

The ratio between the drag force on the jet to the drag force on prop-driven transport is then given by:

$\frac{D_{jet}}{D_{prop}}=\frac{(1/2)Cp_{7.5}Av_{jet}^2}{1/2)Cp_{3.8}Av_{prop}^2} \\\frac{D_{jet}}{D_{prop}}=\frac{p_{7.5}v_{jet}^2}{p_{3.8}v_{prop}}\\\frac{D_{jet}}{D_{prop}}=\frac{(0.53)(1190)^2}{(0.74)(595)^2}\\ \frac{D_{jet}}{D_{prop}}=2.865$

4 0

3 years ago

Consider the rocket in the image. Which unbalanced force accounts for the direction of the net force of the rocket ?

Wittaler [7]

Answer:

unbalenced force

Explanation:

make Brainliest plz

3 0

3 years ago

Read 2 more answers