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Agata [3.3K]
3 years ago
7

How to reduce fluid friction

Physics
1 answer:
kaheart [24]3 years ago
4 0

Answer:

By making the object sharp pointed

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Doc Brown has calculated his Delorean can accelerate at a rate of 2.52 m/s/s. How
GREYUIT [131]

Answer:

304.89m

Explanation:

Given

acceleration a = 2.52m/s²

final speed v = 39.2m/s

initial speed = 0m/s (car accelerates from rest)

Using the equation of motion below to get the distance of Doc brown from Marty;

v² = u²+2as

substitute the given parameters

39.2² = 0²+2(2.52)s

1536.64 = 0+5.04s

divide both sides by 5.04

1536.64/5.04 = 5.04s/5.04

rearrange the equation

5.04s/5.04 = 1536.64/5.04

s = 304.89m

Hence He and Marty must stand at 304.89m to allow the car to accelerate from rest to a speed  of 39.2 m/s?

6 0
3 years ago
In order to convert sunlight energy into usable energy the cell needs
Anestetic [448]

Cells do not use the energy from oxidation reactions as soon as it is released. Instead, they convert it into small, energy-rich molecules such as ATP and nicotinamide adenine dinucleotide (NADH), which can be used throughout the cell to power metabolism and construct new cellular components.

6 0
3 years ago
An object is thrown vertically and has an upward velocity of 18 m/s when it reaches one fourth of its maximum height above its l
Murrr4er [49]

Answer:

v = 25.45 m/s

Explanation:

In order to calculate the initial speed of the object, you take into account the formula for the maximum height reaches by the object. Such a formula is given by:

h_{max}=\frac{v_o^2}{g}   (1)

vo: initial speed of the object = 18 m/s

g: gravitational acceleration = 9.8 m/s²

Furthermore you use the following formula for the final speed of the object:

v^2=v_o^2-2gh       (2)

h: height

You know that the speed of the object is 18m/s when it reaches one fourth of the maximum height. You use this information, and you replace the equation (1) in to the equation (2), as follow:

v^2=v_o^2-2g(\frac{h_{max}}{4})=v_o^2-\frac{1}{2}g(\frac{v_o^2}{g})\\\\v^2=v_o^2-\frac{1}{2}v_o^2=\frac{1}{2}v_o^2

Then, you solve the previous result for vo:

v_o=\sqrt{2}v=\sqrt{2}(18m/s)=25.45\frac{m}{s}

The initial speed of the object was 25.45 m/s

3 0
3 years ago
True or false? Internal motions within the object are used in creating a particle model
nikitadnepr [17]
The answer is true because it is true
5 0
3 years ago
Read 2 more answers
An air-track glider attached to a spring oscillates between the 15.0 cm mark and the 68.0 cm mark on the track. The glider compl
ipn [44]

Answer:

4.42 s

Explanation:

The frequency of the oscillation is given by the ratio between the number of complete oscillations and the time taken:

f=\frac{N}{t}

where for this glider, we have

N = 7.00

t = 31.0 s

Substituting, we find

f=\frac{7.00}{31.0 s}=0.226 Hz

Now we now that the period of oscillation is the reciprocal of the frequency:

T=\frac{1}{f}

So, substituting f = 0.226 Hz, we find:

T=\frac{1}{0.226 Hz}=4.42 s

6 0
3 years ago
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