All categories

4 years ago

What is the 12th term in the addition pattern with formula 6n – 7?

Mathematics

1 answer:

choli [55]4 years ago

8 0

a(n) = 6n - 7
a(12) = 6(12) - 7
a(12) = 72 - 7
a(12) = 65

The answer is B.

You might be interested in

Write a coordinate proof. Prove quadrilateral WXYZ, having vertices W(-5, 6), X(-1, 10), Y(1, 4), and Z(-2, -3) is a trapezoid.

Igoryamba

Answer:

The diagonals are bisectors of each other and meet at (1, -5/2) but are not congruent, so WXYZ is a parallelogram and not a rectangle

Step-by-step explanation:

for parallelograms.

the diagonals intersect at the midpoints

W X

Z Y

Diagonals are WY and XZ

WY : (-4, -3) to (6, -2)

midpoint is [(-4 + 6)/2 , (-3 - 2)/2 ] = ( 1, -5/2 )

XZ : (0, -1) to (2, -4)

midpoint is [ (0 + 2)/2 , (-1 + -4)/2 ] = (1, -5/2)

The diagonals are bisectors of eachother.

Next show that these diagonals are not congruent.

length of WY = root ( (-4 - 6)^2 + (-3 - (-2))^2 )

WY = root ( 100 + 1)

WY = root(101)

length of XZ = root ( (0 - 2)^2 + ( -1 - -4)^2 )

XZ = root (4 + 9) = root (13)

we see that WY is not equal to XZ

...

so .. quadrilateral WXYZ is a parallelogram but not a rectangle.

6 0

4 years ago

Please Help!!

goldenfox [79]

Question 5 is B
Question 9 is C

5 0

3 years ago

Read 2 more answers

Find the Equation of the Parallel Line

sasho [114]

Answer:

y = -5x - 1

Step-by-step explanation:

Let the equation of a line parallel to the given line is,

y - y' = m(x - x')

Where m = slope of the line

And line passes through (x', y')

Equation of a line has been given as,

5x + y = 4

y = -5x + 4

Slope of this line = -5

By the property of parallel lines "slope of the parallel lines are same",

m = -5

Parallel line passing through (-1, 4) and slope 'm' = -5 will be,

y - 4 = -5(x + 1)

y - 4 = -5x - 5

y = -5x - 5 + 4

y = -5x - 1

Therefore, equation of the parallel line will be,

y = -5x - 1

5 0

3 years ago

Will u help me pweessee can u write this down for me so I can copy and past!

alukav5142 [94]

Answer:

Q17: 160=4b+40

Q18: -40 -40

Q19: 120=4b

Q20: /4 /4

Q21: 30=b

Q22: leave b blank

Q23:b = 30

Step-by-step explanation:

your welcome :) have a nice day

5 0

3 years ago

Write the equation of a parabola having the vertex (1, −2) and containing the point (3, 6) in vertex form. Then, rewrite the equ

In-s [12.5K]

PART A

The equation of the parabola in vertex form is given by the formula,

$y - k = a {(x - h)}^{2}$

where

$(h,k)=(1,-2)$

is the vertex of the parabola.

We substitute these values to obtain,

$y + 2 = a {(x - 1)}^{2}$

The point, (3,6) lies on the parabola.

It must therefore satisfy its equation.

$6 + 2 = a {(3 - 1)}^{2}$

$8= a {(2)}^{2}$

$8=4a$

$a = 2$
Hence the equation of the parabola in vertex form is

$y + 2 = 2 {(x - 1)}^{2}$

PART B

To obtain the equation of the parabola in standard form, we expand the vertex form of the equation.

$y + 2 = 2{(x - 1)}^{2}$

This implies that

$y + 2 = 2(x - 1)(x - 1)$

We expand to obtain,

$y + 2 = 2( {x}^{2} - 2x + 1)$

This will give us,

$y + 2 = 2 {x}^{2} - 4x + 2$

$y = {x}^{2} - 4x$

This equation is now in the form,

$y = a {x}^{2} + bx + c$
where

$a=1,b=-4,c=0$

This is the standard form

7 0

3 years ago