25(2) + 7(1) + 3x = 78....x represents the number of 3 point shots
50 + 7 + 3x = 78
57 + 3x = 78
3x = 78 - 57
3x = 21
x = 21/3
x = 7....so there were 7 three-point shots made
Answer:
0.7 + 0.4 - 0.2 = 0.9
Step-by-step explanation:
Let's denote the probabilities as following:
The probability that the show had animals is
P(A) = 0.7
The probability that the show aired more than 10 times is
P(B) = 0.4
The probability that the show had animals and aired more than 10 times is
P(A⋂B) = 0.2
The probability that a randomly selected show had animals or aired more than 10 times is P(A⋃B)
The correct form of addition rule to determine the probability that a randomly selected show had animals or aired more than 10 times is:
P(A⋃B) = P(A) + P(B) - P(A⋂B) = 0.7 + 0.4 - 0.2 = 0.9
=> Option B is correct
Hope this helps!
The correct answer is y = 11
because:
2y + 7 = 3y − 4
−y + 7 =−4
Subtract 7 from both sides.
−y + 7 − 7 = − 4 − 7
−y = −11
Divide both sides by -1.
y = 11
