Answer:
$87,461
Step-by-step explanation:
Given that the dimensions or sides of lengths of the triangle are 119, 147, and 190 ft
where S is the semi perimeter of the triangle, that is, s = (a + b + c)/2.
S = (119 + 147 + 190) / 2 = 456/ 2 = 228
Using Heron's formula which gives the area in terms of the three sides of the triangle
= √s(s – a)(s – b)(s – c)
Therefore we have = √228 (228 - 119)(228 - 147)(228 - 190)
=> √228 (109)(81)(38)
= √228(335502)
=√76494456
= 8746.1109071 * $10
= 87461.109071
≈$87,461
Hence, the value of a triangular lot with sides of lengths 119, 147, and 190 ft is $87,461.
Answer:
BC ≈ 4.85 m
Step-by-step explanation:
Using the cosine ratio in the right triangle
cos26° = 
= 
= 
( cross- multiply )
5.4 × cos26° = BC , then
BC ≈ 4.85 m ( to 3 s f )
Answer:
A
Step-by-step explanation:
20 x 2 = 40
30 x 2 = 60
Answer:
45x + 180 = - 720
Step-by-step explanation:
Let the required number be x.
Therefore, product of 45 and x = 45x
180 added to 45x = 45x + 180
Since, 180 Added to the product of 45 and a number totals negative 720.
So, 45x + 180 = - 720
A) The answer is
x + y + z = 24
3x + 2y + z = 53
x = y + z
x - the number of swimmers in the first place
y - the number of swimmers in the second place
z - the number of swimmers in the third place
<span>1. The e-mail states that 24 individuals placed: x + y + z = 24
2. </span>First place earned 3 points, second place earned 2 points, and third place earned 1 point, <span>earning a combined total of 53 points: 3x + 2y + z = 53
3. </span><span> There were as many first-place finishers as second and third-place finishers combined: x = y + z
The system of three equations is:
</span>x + y + z = 24
3x + 2y + z = 53
x = y + z
B) The answer is
12 swimmers in the first place
5 swimmers in the second place
7 swimmers in the third place
(i) x + y + z = 24
(ii) 3x + 2y + z = 53
(iii) x = y + z
______
Substitute y + z from the third equation into the first one:
(i) x + y + z = 24
(iii) x = y + z
______
x + x = 24
2x = 24
x = 24 / 2
<u>x = 12</u>
_____
x = y + z
x = 12
y + z = 12
z = 12 - y
3x + 2y + z = 53
3 * 12 + 2y + (12 - y) = 53
36 + 2y + 12 - y = 53
2y - y + 36 + 12 = 53
y + 48 = 53
y = 53 - 48
<u>y = 5</u>
z = 12 - y
z = 12 - 5
z = 7
