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cluponka [151]
3 years ago
15

Explain this three questions please

Mathematics
1 answer:
serious [3.7K]3 years ago
4 0
For the #2 it would be 3 because 50 goes into 138 2 times which will give you 100 with a remainder of 38. You can't leave behind the other 38 so you will bring another bus.
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Here's another Math one worth 10.
tia_tia [17]
<span>In a 30-60-90  triangle the side opposite the 30 degree angle is half the length of the hypotenuse. 
The short leg is </span>the side opposite the 30 degree angle. If the short leg =x, then the hypotenuse = 2x

The ratio of the short leg to the hypotenuse in the given triangle is cos(60°)

&#10;cos(60^o) = \frac{adjacent \ side}{hypotenuse  } =  \frac{x}{2x} = \frac{1}{2}

Answer is C. 1:2
7 0
3 years ago
What is 4 3/4 of rupee 1
devlian [24]

Answer:

\frac{19}{4}=Rs 1

Rs. 1 = 100 paise

\frac{19}{4}=100 paise

4.75=100 paise

\frac{4.75}{100}=paise

0.0475=paise

i hope this will help you :)

=1,075

Therefore,

\frac{43}{4} =1,075

Hope it helps you!!!

Plz Mark me as a brailiest

Step-by-step explanation:

5 0
3 years ago
PLS HURRY!!<br> Simplify.<br> 7/3+3(2/3−1/3)^2 Enter your answer in the box.
AveGali [126]

Do distributed property   7/3+3(2/3-1/3)^2 7/3+3×(2/3-1/3)^2 7/3+3×(1/3)^2 7/3×3×1/9 7/3×1/3 7+1/3 8/3 or 2 and 2/3 or 2.66667

3 0
4 years ago
Read 2 more answers
You have a cubr that is 4in.x 4in.x4.in what is the surface area​
hodyreva [135]

Answer:

SA = 96 in ^2

Step-by-step explanation:

Since the figure is a cube, we know that the surface area is given by

SA = 6 s^2  where s is the side length

SA = 6 * 4^2

SA = 6*16

SA = 96 in ^2

7 0
3 years ago
Question 1 (Essay Worth 10 points) (01.02 MC) Part A: If (26)x = 1, what is the value of x? Explain your answer. (5 points) Part
katen-ka-za [31]

Answer:

See Explanation

Step-by-step explanation:

The question is not clear. However, I will treat the question as:

(26)x = 1

(50)x = 1

and:

(2^6)^x = 1

(5^0)^x = 1

Solving: (26)x = 1  and  (50)x = 1

(26)x = 1

Divide both sides by 26

x = \frac{1}{26}

(50)x = 1

Divide both sides by 50

x = \frac{1}{50}

Solving (2^6)^x = 1 and (5^0)^x = 1

(2^6)^x = 1

Express 1 as 2^0

(2^6)^x = 2^0

Remove bracket

2^{6x} = 2^0

Cancel out 2

6x = 0

Divide both sides by 6

x = \frac{0}{6}

x = 0

(5^0)^x = 1

Express 1 as 5^0

(5^0)^x = 5^0

Cancel out 5^0

x = 1

8 0
3 years ago
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