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Firdavs [7]
4 years ago
5

Your spaceship lands on an unknown planet. To determine the characteristics of this planet, you drop a wrench from 5.00 m above

the ground and measure that it hits the ground 0.804 s later. Part APart complete What is the acceleration of gravity near the surface of this planet
Physics
1 answer:
GenaCL600 [577]4 years ago
4 0

Answer:

g = 15.5 m/s²

Explanation:

In order to find the acceleration due to gravity near the surface of this planet can be calculated by using 2nd equation of motion. The 2nd equation of motion is given as:

h = Vi t + (0.5)gt²

where,

h = height covered by the wrench = 5 m

Vi = Initial Velocity = 0 m/s

t = Time Taken to hit the ground = 0.804 s

g = acceleration due to gravity near the surface of the planet = ?

Therefore,

5 m = (0 m/s)(0.804 s) + (0.5)(g)(0.804 s)²

g = (5 m)/(0.3232 s²)

<u>g = 15.5 m/s²</u>

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3 years ago
A 1kg skateboard sits at the top of a ramp 20 fr off the ground . How much potential energy does it have ?
Finger [1]

Answer:

196J

Explanation:

Given parameters:

Mass of skateboard  = 1kg

Height off the ground  = 20m

Unknown:

Potential energy  = ?

Solution:

The potential energy is the energy due to the position of a body above the ground.

It is mathematically expressed as:

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8 0
3 years ago
Which is the most likely reason why scientists change a model?
ASHA 777 [7]

Answer:

hypothesis

Explanation:

5 0
3 years ago
What is the wavelength of red light in vacuum that has a frequency of 4.00 × 1014 hz?
Pachacha [2.7K]

Answer: 7.5(10)^{-7} m

Explanation:

The frequency \nu of an electromagnetic wave is given by the following equation:  

\nu=\frac{c}{\lambda}  

Where:  

c=3(10)^{8} m/s is the speed of light  in vacuum

\nu=4(10)^{14} Hz is the frequency of red light

\lambda   is the wavelength of red light

Isolating \lambda:

\lambda=\frac{c}{\nu}  

\lambda=\frac{3(10)^{8} m/s}{4(10)^{14} Hz}  

Finally:

\lambda=7.5(10)^{-7} m  

6 0
4 years ago
Calculate the work done by a 47 n force pushing a 0.025 kg pencil 0.25 m against a force of 23.
inna [77]
Fnet=fa-fr
=47-23
=24n
W=F∆Xcos°
=24n×0.025cos0
=0.6J
8 0
3 years ago
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