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melamori03 [73]
4 years ago
12

Insulating concrete forms (ICFs): Select one: a. place the insulation at the core of the concrete wall. b. can be filled with co

ncrete in a high-lift operation. c. come in entire-wall size. d. are interlocking blocks that can be placed easily. e. are forms made of insulating concrete.
Engineering
1 answer:
Hitman42 [59]4 years ago
3 0

Answer:

Insulating Concrete forms (ICFs) a. place the insulation at the core of the concrete wall. This insulation is like a framework made from materials like polystyrene foam or cement bonded wood fiber etc and is placed at the core of the wall. These concrete walls have the long life time, strength and also provide protection from fire.

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A particular electromagnetic wave travelling in vacuum is detected to have a frequency of 3 × 10 12 Hz. How much time will it ta
irina1246 [14]

3×10^-12 seconds

Explanation:

T=1/f

7 0
2 years ago
A reciprocating engine of 750mm stroke runs at 240 rpm. If the length of the connecting rod is 1500mm find the piston speed and
Sedbober [7]

Answer:

speed = 16.44 m/s

Acceleration = 71.36 m/s²

Explanation:

Given data

Speed ( N) = 240 rpm

angle  = 45°

stoke length(L)  = 750 mm

length of rod ( l )  = 1500 mm

To find out

the piston speed and acceleration

Solution

we find speed by this formula

speed = r ω (sin(θ) + (sin2(θ)/ 2n))  ...................1

here we have find  r and ω

ω = 2\pi N / 60

so ω = 2\pi × 240 / 60

ω =  25.132 rad/s

n = l/r =  1500/750 = 2

we know  L = 2r

so r = L/2 = 750/2 = 375 mm

put these value in equation 1

speed = 375 × 25.132 (sin(45) + (sin2(45)/ 2×2))  

speed = 16444.811823 mm/s = 16.44 m/s

Acceleration = r ω² (cos(θ) + (cos2(θ)/ n))  ...................2

put the value  r, ω and n in equation 2

Acceleration = r ω² (cos(θ) + (cos2(θ)/ n))

Acceleration  = 375 × (25.132)² (cos(45) + (cos2(45)/2))  

Acceleration = 71361.363659 = 71.36 m/sec²

3 0
4 years ago
simply supported beam is subjected to a linearly varying distributed load ( ) 0 q x x L 5 q with maximum intensity 0 q at B. The
Pavlova-9 [17]

Answer:

q₀ = 350,740.2885 N/m

Explanation:

Given

q(x)=\frac{x}{L} q_{0}

σ = 120 MPa = 120*10⁶ Pa

L=4 m\\w=200 mm=0.2m\\h=300 mm=0.3m\\q_{0}=? \\

We can see the pic shown in order to understand the question.

We apply

∑MB = 0  (Counterclockwise is the positive rotation direction)

⇒ - Av*L + (q₀*L/2)*(L/3) = 0

⇒ Av = q₀*L/6   (↑)

Then, we apply

v(x)=\int\limits^L_0 {q(x)} \, dx\\v(x)=-\frac{q_{0}}{2L} x^{2}+\frac{q_{0} L}{6} \\M(x)=\int\limits^L_0 {v(x)} \, dx=-\frac{q_{0}}{6L} x^{3}+\frac{q_{0} L}{6}x

Then, we can get the maximum bending moment as follows

M'(x)=0\\ (-\frac{q_{0}}{6L} x^{3}+\frac{q_{0} L}{6}x)'=0\\ -\frac{q_{0}}{2L} x^{2}+\frac{q_{0} L}{6}=0\\x^{2} =\frac{L^{2}}{3}\\  x=\sqrt{\frac{L^{2}}{3}} =\frac{L}{\sqrt{3} }=\frac{4}{\sqrt{3} }m

then we get  

M(\frac{4}{\sqrt{3} })=-\frac{q_{0}}{6*4} (\frac{4}{\sqrt{3} })^{3}+\frac{q_{0} *4}{6}(\frac{4}{\sqrt{3} })\\ M(\frac{4}{\sqrt{3} })=-\frac{8}{9\sqrt{3} } q_{0} +\frac{8}{3\sqrt{3} } q_{0}=\frac{16}{9\sqrt{3} } q_{0}m^{2}

We get the inertia as follows

I=\frac{w*h^{3} }{12} \\ I=\frac{0.2m*(0.3m)^{3} }{12}=4.5*10^{-4}m^{4}

We use the formula

σ = M*y/I

⇒ M = σ*I/y

where

y=\frac{h}{2} =\frac{0.3m}{2}=0.15m

If M = Mmax, we have

(\frac{16}{9\sqrt{3} }m^{2} ) q_{0}\leq \frac{120*10^{6}Pa*4.5*10^{-4}m^{4}   }{0.15m}\\ q_{0}\leq 350,740.2885\frac{N}{m}

8 0
4 years ago
1 A power transmission includes a belt drive, a chain drive and a gear drive. Which of the following is the best arrangement bet
Setler79 [48]

Answer:d

Explanation:

(d) chain drive belt drive gear drive

3 0
3 years ago
Can i use two shunts and one meter
Lyrx [107]

Answer:

no

Explanation:

6 0
3 years ago
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