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Molodets [167]
3 years ago
6

Suppose a student rubs a Teflon rod with wool and then briefly touches it to an initially neutral aluminum rod suspended by insu

lating threads. What would the net charge on the Teflon rod be? What would the net charge on the aluminum rod be? After the student has touched the aluminum rod with the rubbed Teflon rod, as described above, the student then holds the Teflon rod near the aluminum rod, but does not allow them to touch. The student observes that when the rods are close enough tog
Engineering
1 answer:
Oliga [24]3 years ago
3 0

Answer:

Due to touch of teflon, its charge will reduce but will not go to zero. Some amount of its initial charge will be transferred to Aluminum rod. So, aluminum rod will have a non-zero negative charge.

Explanation:

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Which of the following team members would not be involved in the design of
dimulka [17.4K]

Answer:

Writer

Explanation:

5 0
2 years ago
If gain of the critically damped system is increased, the system will behave as a) Under damped b) Over damped c) Critically dam
Ganezh [65]

Answer:

a) Under damped

Explanation:

Given that system is critically damped .And we have to find out the condition when gain is increased.

As we know that damping ratio given as follows

\zeta =\dfrac{C}{C_c}

Where C is the damping coefficient and Cc is the critical damping coefficient.

C_c=2\sqrt{mK}

So from above we can say that

\zeta =\dfrac{C}{2\sqrt{mK}}

\zeta \alpha \dfrac{1}{\sqrt K}

From above relationship we can say when gain (K) is increases then system will become under damped system.

7 0
3 years ago
Which term defines the amount of mechanical work an engine can do per unit of heat energy it uses?
skad [1K]

Answer:

d

Explanation:

is the because that's the amount of work in making machine can do producing heat

7 0
3 years ago
A long, horizontal, pressurized hot water pipe of 15cm diameter passes through a room where the air temperature is 24degree C. T
solmaris [256]

Answer:

Rate of heat transfer to the room air per meter of pipe length equals 521.99 W/m

Explanation:

Since it is given that the radiation losses from the pipe are negligible thus the only mode of heat transfer will be by convection.

We know that heat transfer by convection is given by

\dot{Q}=hA(T-T_{\infty })

where,

h = heat transfer coefficient = 10.45 W/m^{2}K (free convection in air)

A = Surface Area of the pipe

Applying the given values in the above formula we get

\dot{Q}=10.45\times \pi DL\times (130+273-(24+273))\\\\\frac{\dot{Q}}{L}=10.45\times 0.15\times \pi \times (130-24)\\\\\frac{\dot{Q}}{L}=521.99W/m

5 0
3 years ago
A 20 kg mass is thrown from the ground to a height of 50 m. (a) find the kinetic energy of the mass at this height. (b) find the
horrorfan [7]

Answer:

(a) 0 kJ

(b) 9.81 kJ

(c) 31.32 m/s

Explanation:

(a)

From the law of conservation of energy, energy can only be transformed from one state to another. At a height of 50 m, all the kinetic energy is converted to potential energy hence KE=0

(b)

Potential energy, PE=mgh where m is the mass, g is acceleration due to gravity and h is the height

Substituting 50 m for h and 20 Kg for m, taking g as 9.81 then

PE=20*9.81*50=9810 J=9.81 kJ

(c)

Relating the equation of potential energy to the equation of kinetic energy, which is 0.5mv^{2}

mgh=0.5mv^{2} where v is the velocity of the mass

v=\sqrt {2gh}

Substituting 50 m for h and taking g as 9.81 then

v=\sqrt {2*9.81*50}=31.32091953\approx 31.32 m/s

3 0
2 years ago
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