Answer:
Option D. 0.9mol x 2mol Fe /3mol CO2 x 55.845g Fe /1mol Fe
Explanation:
The balanced equation for the reaction is given below:
3CO + Fe₂O₃ → 2Fe + 3CO₂
Molar Mass of Fe = 56g/mol
From the balanced equation above,
3 moles of CO2 produced (2 mol Fe x 55.845g Fe.
Therefore, 0.9 mole of CO2 will produce = 0.9mol x 2mol Fe /3mol CO2 x 55.845g Fe /1mol Fe
I can't seem to tell which one is the first row since there is no table. So, I'll just fill in all the question marks for you.
<span>Name: Boyle's Law
Variables: pressure and volume
Constants = gas constant and temperature
PV = k
</span><span>Charles’s law
Volume and temperature
Gas constant and pressure
V = kT
</span><span>Gay-Lussac's Law
Temperature, pressure
Gas constant and volume
P = kT
</span><span>Combined gas law
Pressure, temperature, volume
Gas constant and moles of gas
PV=kT
The answers are those in bold letters for each section. Just see all of the sections so that you can see which one corresponds to the first row.</span>
Given: Age of sample = 555
Half life = 111
So, number of half life =
=
= 5
Thus, number of half life of radioactive sample is 5
Which list of elements contains a metal, a metalloid, and a nonmetal?(1) Zn, Ga, Ge (3) Cd, Sb, I(2) Si, Ge, Sn (4) F, Cl, Br
Sladkaya [172]
3) Cd . Sb . I
<span>look at the periodic chart- if the element is on the right it is a nonmetal, if it is on the left its a metal, and if it is in between it is a metalloid</span>
Answer:
1.23 j/g. °C
Explanation:
Given data:
Mass of metal = 35.0 g
Initial temperature = 21 °C
Final temperature = 52°C
Amount of heat absorbed = 320 cal (320 ×4.184 = 1338.88 j)
Specific heat capacity of metal = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 52°C - 21 °C
ΔT = 31°C
1338.88 j= 35 g ×c× 31°C
1338.88 j= 1085 g.°C ×c
1338.88 j/1085 g.°C = c
1.23 j/g. °C = c