Answer:
your answer would be : examples such as Thallium-206, Lead-210, & Bismuth-214.
The equilibrium constant (K) : 11.85
<h3>Further explanation</h3>
Given
Reaction
N₂(g) + 3H₂(g) ⇒ 2NH₃(g)
Required
K(equilibrium constant)
Solution
The equilibrium constant (K) is the value of the concentration product in the equilibrium
The equilibrium constant based on concentration (K) in a reaction
pA + qB -----> mC + nD
![\tt K=\dfrac{[C]^m[D]^n}{[A]^p[B]^q}](https://tex.z-dn.net/?f=%5Ctt%20K%3D%5Cdfrac%7B%5BC%5D%5Em%5BD%5D%5En%7D%7B%5BA%5D%5Ep%5BB%5D%5Eq%7D)
For the reaction above :
![\tt K=\dfrac{[NH_3]^2}{[N_2][H_2]^3}\\\\K=\dfrac{0.1^2}{0.25\times 0.15^3}\\\\K=11.85](https://tex.z-dn.net/?f=%5Ctt%20K%3D%5Cdfrac%7B%5BNH_3%5D%5E2%7D%7B%5BN_2%5D%5BH_2%5D%5E3%7D%5C%5C%5C%5CK%3D%5Cdfrac%7B0.1%5E2%7D%7B0.25%5Ctimes%200.15%5E3%7D%5C%5C%5C%5CK%3D11.85)
Answer;
Mass in gram/molecular mass=no.of molecule of Cl2 gas/Avogadro’s number(NA) - - - - - - - - -(1)
Here,
Molecular mass of cl2=35.5*2=71
No.of cl2 molecule=5*10^22
Avogadro’s number(NA)=6.032*10^23
Now,substituting these all value in equation one,we get,
Mass in gram =(no.of molecule)/NA)*molecular mass
Or,Mass in gram =(5*10^22/6.023*10^23)*71
Or,Mass in gram = 5.89gm.Ans
Answer:
D. the total mass that element contribute to a molecule