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3 years ago

To prove that the triangles are similar by the SAS similarity theorem, it needs to be shown that

Mathematics

1 answer:

vesna_86 [32]3 years ago

3 0

Answer:

The triangle has two sides that are equivalent and the angle where the two meet are also equivalent.

In other words, two sides and the angle between them are congruent.

Hope this helps, if it does please give me brainliest, it will help me a lot :)

Have a good day

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Hiii please help i’ll give brainliest:)

djverab [1.8K]

Answer:

Geographic features of ancient Greece.

Step-by-step explanation:

Greece has all of those attributes.

6 0

2 years ago

A tortoise moves at a speed of 34 inches in 11 seconds. What is its average speed in feet per hour?

Elan Coil [88]

Answer:

927.3 feet per hour

Step-by-step explanation:

first determine how many seconds are in one hour

there are 60 seconds in one minute and 60 minutes in one hour

so there are 60x60, or 3600 seconds in one hour

now you can create a proportion of inches/seconds = inches/seconds

let 'x' = inches per hour

34/11 = x/3600

cross-multiply to get:

11x = 3600x34

11x = 122,400

x = 122,400/11

x = 11,127.3 inches per hour

to determine how many feet per hour you must divide 11,127.3 inches by 12

this equals 927.3 feet per hour

3 0

2 years ago

8.006 minus 6.38 awnser

Nutka1998 [239]

8.006
-6.38 = 1.626

Hope this help

3 0

3 years ago

Which statement is true using Cavalieri’s principles ?

Kay [80]

Answer:

One of the benefits of Cavalieri's principle is that it allows us to determine the volume of an oblique prism (or oblique cylinder). When dealing with two prisms (or two cylinders), if the base areas are equal and the heights are equal, then the volume is V = Bh regardless of the overall shape.

( i cant see the answers well so estimate to the one that applies)

5 0

3 years ago

Which two values of x are roots of the polynomial below?<br> x2-11x + 15

Alex787 [66]

The two values of roots of the polynomial $x^{2}-11 x+15$ are $\frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}$

<u>Solution:</u>

Given, polynomial expression is $x^{2}-11 x+15$

We have to find the roots of the given expression.

In order to find roots, now let us use quadratic formula.

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Given that $x^{2}-11 x+15$

Here a = 1, b = -11 and c = 15

On substituting the values we get,

$x=\frac{-(-11) \pm \sqrt{(-11)^{2}-4 \times 1 \times 15}}{2 \times 1}$

$\begin{array}{l}{x=\frac{11 \pm \sqrt{121-60}}{2}} \\\\ {x=\frac{11 \pm \sqrt{61}}{2}} \\\\ {x=\frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}}\end{array}$

Hence, the roots of given polynomial are $\frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}$

6 0

3 years ago