How do you do this??
1 answer:
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The bus stop method is just like division.
Ex
137÷5=
1.) 5 goes into one zero times so there is a zero on top.
2.) 5 goes into 13 two times, so after the zero there is a 2.
3.) 5 goes into 37 seven times so there is a 7 after the 2.
4.) There is a 2 left and five can't go into school therefore that is a remainder.
027R2
5/137
<u>- 10</u>
37
<u>-35</u>
2
Hoped I helped:D
Ex
137÷5=
1.) 5 goes into one zero times so there is a zero on top.
2.) 5 goes into 13 two times, so after the zero there is a 2.
3.) 5 goes into 37 seven times so there is a 7 after the 2.
4.) There is a 2 left and five can't go into school therefore that is a remainder.
027R2
5/137
<u>- 10</u>
37
<u>-35</u>
2
Hoped I helped:D
Take log of both sides
Use log property to get "x" out of the exponent
Differentiate
Move y to Right side (Note y = original expression)
In general, whenever you have a function in the form
The derivative will be
Use log property to get "x" out of the exponent
Differentiate
Move y to Right side (Note y = original expression)
In general, whenever you have a function in the form
The derivative will be