Answer:
you multiply each individual number by 1/3, and subtract 1 from it.
Hello from MrBillDoesMath!
Answer:
27 x^2 sqrt(x^3) sin(x^3) - 9/2 sqrt(x^1/2) sin(x^1/2)*x^(-1/2)
Discussion:
Let f(t) - 9 sqrt(t) sin(t), then
y' = f(x^3) * d(x^3)/dx - f(sqrt(x)) * d(x^1/2)/dx
= (9 sqrt(x^3)sin(x^3)) * 3x^2 - (9 sqrt(x^1/2)sin(x^1/2)) * (1/2) x^-(1/2)
= 27 x^2 sqrt(x^3) sin(x^3) - 9/2 sqrt(x^1/2) sin(x^1/2)*x^(-1/2)
Hope I didn't make a "bozo" error differentiating things!
Thank you,
MrB
No, because (2,0) is a coordinate. x=2 and y=0. So just plug in the numbers where there's x or y with the appropriate number, (2 or 0). So in the first equation, x-2y=0, when you pug in the numbers, 2-2(0)=0, you know it's wrong because 2-0=0 isn't correct. So no. the point (2,0) is not a solution to the first equation. Now plug in the numbers for the second coordinate. You get 2(2)-3(0)=1. So 4-0=1. This is once again false no no. (2,0) satisfies neither equations.
The equation is V = PI x r^2 x h
r = 1/2 the diameter = 4.5
Volume = 3.14 x 4.5^2 x 5
Volume = 317.9 cm^3
