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shusha [124]
3 years ago
15

Assistance with polynomials

Mathematics
1 answer:
TiliK225 [7]3 years ago
4 0
Should be the second one. 
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otez555 [7]
16)\ \sqrt{32k}=\sqrt{16\cdot2k}=\sqrt{16}\cdot\sqrt{2k}=4\sqrt{2k}\\\\18)\ \sqrt{216x^4}=\sqrt{36\cdot (x^2)^2\cdot6}=\sqrt{36}\cdot\sqrt{(x^2)^2}\cdot\sqrt6=6x^2\sqrt6\\\\20)\ \sqrt{8m^2n^2}=\sqrt{4\cdot m^2\cdot n^2\cdot2}=\sqrt4\cdot\sqrt{m^2}\cdot\sqrt{n^2}\cdot\sqrt2=2mn\sqrt2

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