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shusha [124]
3 years ago
15

Assistance with polynomials

Mathematics
1 answer:
TiliK225 [7]3 years ago
4 0
Should be the second one. 
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1/3 divided by 1/8<br> a, 1/24<br> b. 3/8<br> C. 2 and 2/3<br> d. 24
Degger [83]
The answer is B. 3/8
5 0
2 years ago
Read 2 more answers
Sidney skated for 1 1/10 hours last month and 8 7/10 hours this month. How many
olganol [36]

Answer:

the number of hours does sidney skate in all is 9.8 hours

Step-by-step explanation:

The computation of the number of hours does sidney skate in all is as follows:

= Last month + this month

= 1 \frac{1}{10} + 8 \frac{7}{10}\\\\= \frac{11}{10} + \frac{87}{10}\\\\= \frac{98}{10}

= 9.8 hours

Hence, the number of hours does sidney skate in all is 9.8 hours

3 0
3 years ago
Which of the following is equal to the rational expression when x=-1 or -7? (x+1)(x-1)/(x+7)(x+1) a. x+7/x-1 b. x-1/x+7 c. x+1/x
e-lub [12.9K]

Answer:b

Step-by-step explanation:

(×+1)(×-1)

---------------

(×+1)(×+7)

=cancel (×+1) both the numerator and denominator then you are left with

(×-1)

-------

(×+7)

=(×-1)/(×+7)

5 0
3 years ago
A store that sells skis boys them from a manufacturer at a wholesale price of $57. The
Over [174]

Answer:

50 = 2

Step-by-step explanation:

which by definition equates to 68+1

3 0
3 years ago
A tennis coach took his team out for lunch and bought 8 hamburgers and 5 fries for $24. The players were still hungry so the coa
g100num [7]

The cost of 1 hamburger is $ 2.5 and cost of 1 fries is $ 0.8

<h3><u>Solution:</u></h3>

Let "f" be the cost of 1 fries

Let "h" be the cost of 1 hamburger

<em><u>Given that, tennis coach took his team out for lunch and bought 8 hamburgers and 5 fries for $24</u></em>

8 x cost of 1 hamburger + 5 x cost of 1 fries = 24

8 \times h + 5 \times f = 24

8h + 5f = 24 -------- eqn 1

<em><u>The players were still hungry so the coach bought six more hamburgers and two more fries for $16.60</u></em>

6 x cost of 1 hamburger + 2 x cost of 1 fries = 16.60

6 \times h + 2 \times f = 16.60

6h + 2f = 16.60 ------ eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Multiply eqn 1 by 2

16h + 10f = 48 ------ eqn 3

Multiply eqn 2 by 5

30h + 10f = 83 -------- eqn 4

<em><u>Subtract eqn 3 from eqn 4</u></em>

30h + 10f = 83

16h + 10f = 48

( - ) ----------------------

14h = 35

<h3>h = 2.5</h3>

Substitute h = 2.5 in eqn 1

8(2.5) + 5f = 24

20 + 5f = 24

5f = 4

<h3>f = 0.8</h3>

Thus cost of 1 hamburger is $ 2.5 and cost of 1 fries is $ 0.8

5 0
3 years ago
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