Answer:
Therefore the value of x = 10 units
Step-by-step explanation:
Let label the Triangles first,
Δ ABC a right triangle at ∠ A =90°
Δ ADB andΔ ADC a right triangle at ∠ D =90°
Such that
AD = x
BD = 50
CD = 2
∴ BC = BD + DC = 50 + 2 = 52
To Find:
x = ?
Solution:
In right triangle By Pythagoras Theorem,
In right triangle Δ ADB andΔ ADC By Pythagoras Theorem we will have,
AB² = BD² + AD²
AB² = 50² + x² ..................equation ( 1 )
and
AC² = DC² + AD²
AC² = 2² + x² ...................equation ( 2 )
Now in right triangle Δ ABC,
BC² = AB² + AC²
Equating equation (1 ) and ( 2 ) and the given value we get
52² = 50² + x² + 2² + x²
∴ 2x² = 2704 - 2504
∴ 2x² =200
∴ 
Therefore the value of x = 10 units
I believe there are 20 quarters and 3 nickels.....
Total value of the jar is $5.15.....
Quarters are worth 25 cents
And nickels are worth 5 cents.
First you know that there are 4 quarters in a dollar.
You have 5 dollars so you do 4 x 5 = 20
So five dollars ($5.00) is 20 quarters.
And you still have 15 cents left.
Because quarters are 25 cents the rest are nickels.
Nickels are worth 5 cents so you'd do 5 x 3 = 15.
15 cents!
Add all this together and get $5.15.
So your answer is
There are 20 quarters and 3 nickels in the jar.
If the given radius is 5 inches, then the circumference, C is 2pi r, or 2pi(5 inches) = 10pi inches. You MUST include pi in your calculation of C.
<h3>
Answer: g(x) = (-2/3)x^2</h3>
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Explanation:
The blue parent function has a positive coefficient of 1. The purple g(x) function is a reflection of f(x) over the x axis, so everything is now negative. The coefficient must be negative as well.
But the answer is simply not g(x) = -x^2 because plugging x = 3 does not lead to y = -6 as the point (3,-6) shows.
Let's say the coefficient is k for now. So we have y = kx^2
Plug in x = 3 and y = -6. Solve for k
y = kx^2
-6 = k(3)^2
-6 = k*9
9k = -6
k = -6/9
k = -2/3
So we update y = kx^2 into y = (-2/3)x^2
Meaning that g(x) = (-2/3)x^2 is the equation of the purple curve.
Plug x = 3 into g(x) to find that
g(x) = (-2/3)x^2
g(3) = (-2/3)(3)^2
g(3) = (-2/3)(9)
g(3) = -6
which is the output we want, so this confirms we have the correct coefficient.
